I am having two questions:
- Does every separable Hilbert Space have a Schauder Basis?
Proof: Every Hilbert Space $H$ has a total orthonormal set say $E=\{e_i\}_{i\in I}$. Since $H$ is separable to $E$ is countable then $E=\{e_k\}_{k\in \Bbb N}$.
Then $E$ is a Schauder Basis of $H$.
Since $E$ is total so $\text{span E}$ is dense in $H$ hence given $x\in H$ there exists a sequence $x_n\to x$ such that $||x_n-x||\to 0$ where $x_n=\sum_{i=1}^m c_{ni}e_i$.
Is it correct?
- I know that every normed space has a Hamel Basis since they are all vector spaces.What is an example of a normed space which has no Schauder Basis?
Your reasoning is correct. Another way of proving this, is to take an countable dense set, and then apply Gram-Schmidt procedure to generate an orthonormal Schauder basis.
As to your second question: If a normed space has a Schauder basis, then the space is separable, since the set of finite linear combinations of basis vectors with rational (complex) coefficients is countable and dense. Hence, non-separable spaces do not admit a Schauder basis.