can anyone help me with this question especially the first one...I don't know how to find the equation of the line as i'm only given one point.
2026-03-26 04:53:18.1774500798
Functions and Graphs - How to find equation of a straight line with only 1 given point
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First, you need to find the point Q. Because the parabola is symmetric about the axis of symmetry, $x = 3$, if $(1,0)$ is on the parabola, then $(5,0)$ is Q. Now we have two points on the line, $(-3,4)$, and $(5,0)$. I'm sure you can find the slope and use the point-slope formula to figure out the equation line.
Now to find the equation of the parabola, just use the vertex form: $y = a(x-h)^2 + k$. The vertex, $(h,k)$ is $(3,2)$. Plug in $3$ for $h$, and $2$ for $k$. Now, plug in $1$ (or $5$) for $x$, and $0$ for $y$. From this, you should be able to figure out a.