$Gal(\bar{\mathbb Q}/\mathbb Q)$ without choice, and constructive Galois theory

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By this question: Algebraic closure for $\mathbb{Q}$ or $\mathbb{F}_p$ without Choice? We have that over ZF, algebraic closures of $\mathbb Q$ aren't unique. Are their Galois groups as extensions over $\mathbb Q$ still isomorphic? In general, what other obstructions to doing constructive Galois theory over $Gal(\bar{\mathbb Q}/\mathbb Q)$ might we run into?