gaussian curvature in isotherm parameterization

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Consider an isothermic parameterization with metric $$(g_{ij}) = \begin{bmatrix} \lambda^2 & 0 \\ 0 & \lambda^2\end{bmatrix}$$ with $\lambda = \lambda(u^1,u^2)>0$. Then the gaussian curvature can be calculated by $$K=\frac{\lambda_1^2+\lambda_2^2}{\lambda^4} -\frac{\lambda_{11}+\lambda_{22}}{\lambda^4}$$

I know that I can get the curvature as the determinant of the Weingarten map or as the quotient of the determinant of the second and first fundamental form, but I don't quite know how I can get to this just from the given metric.

Can anyone point me to the right direction with this? Thanks.

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You need the Gauss equation, most conveniently in an orthogonal parametrization. See most any differential geometry text, including my own :)