$\gcd(|G|, |\text{Aut}(G)|)=1$ means G is abelian?

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Prove the following assuming that $G$ is finite group with $\gcd(|G|, |\text{Aut}(G)|)=1$.

a) G is abelian (done).

b) Every Sylow subgroup of $G$ is cyclic of prime order.

Since G is abelian than every Sylow subgroup is unique, but does it mean cyclic?

Any suggestion?