A family $\mu$ of coverings of a set $X$ is called a covering uniformity if it satisfies the following conditions:
- If $\frak U,\frak V\in\mu$ there is a $\frak W\in\mu$ with $\frak W\prec \frak U$ and $\frak W\prec \frak V$,
- every element of $\mu$ has a star refinement in $\mu$,
- if $\frak U\in\mu$ and $\frak U\prec \frak W$ then $\frak W\in\mu$.
Let us note that, A basis for a covering uniformity is a family of coverings that satisfies conditions (1) and (2).
Now If $\mathcal U$ is an entourage uniformity for $X$, for each $U\in\mathcal U$, let $\mathfrak{T}_U= \{ U[x]:x\in X \}$ and put $\mu=\{\mathfrak{T}_U:U\in\mathcal U\}$.
then $\mu$ is a covering uniformity or a basis for a covering uniformity? i can show that $\mu$ satisfies conditions (1) and (2).
These uniform covers $\mathfrak{T}_U$ only form a base for the covering uniformity.
Quote from Willard, General Topology (p. 245)
The usual approach is to take a base for the entourage uniformity and the corresponding uniform covers form a base for a covering uniformity, and vice versa, if we have a covering uniformity with base $\{\mathfrak{U}_i : i \in I\}$ then the entourages $U_i = \cup \{ U \times U : U \in \mathfrak{U}_i\}$ for a base for an entourage uniformity. These uniformities generate the same topology etc., and are equivalent (also in uniform sense). See exercise 36C in Willard.