I have the following problem:
Find three positive numbers which have the sum of $70$ and create a Geometric progression ($q>0$, increasing). Their inverse sum equals to $4/70$.
Thank you!
2026-04-08 06:34:42.1775630082
Geometric progression with reverse order
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Hint: You need to write equations to express the facts you are given. As it is a geometric progression with ratio $q$, the numbers are $a, aq, aq^2$. Their sum is $70$. Can you write that as an equation? I would presume inverse sum means the sum of their inverses, so write that as an equation. You have two equations in two unknowns.