Differentiate both sides of the geometric sum with respect to $r$.$$\sum_{i=0}^n r^i = \frac{1-r^{n+1}}{1-r}$$ Use the result to show that $$\sum_{i=1}^n ir^i < \frac{r}{(1-r)^2} \text{ for all } n\ge1 .$$
2026-04-24 08:04:04.1777017844
Geometric summation question
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