I don't get.. The largest side of the triangle (side a) is 10 more units that the smallest side (side b) and the 3rd side of the triangle(side c) is triple the smallest side of the triangle. if the perimeter is 125 units how many units is each side.
A+10=The perimeter of the Largest side of the triangle B*3=the Perimeter of the 3rd side Of the triangle C=the Perimeter of the smallest side of the triangle P= 125 units
Use algebra to solve this. Let $a$ be the longest side, $b$ the middle-length side, and $c$ the shortest side. We can write the following three equations: $$a = c + 10,$$ $$b = 3c,$$ $$a + b + c = 125.$$
To solve this system, substitute the first two equations in terms of $c$ into the third equation. This yields $5c + 10 = 125,$ so $c = 23.$ It follows that $a = 33$ and $b = 69.$
However, notice that $a < c,$ which leads to a contradiction. In addition, the three lengths found here cannot form a triangle, as $a + c = 56 < b = 69.$ Therefore, there is $\text{NO SOLUTION}.$