Getting a differential equation from a parametric function family

Question

I have two parametric function families and i need to find the differential equation they satisfy.
I'm very lost on this one. I tried to write $y=y(x)$ using similarities between the two families.
But i couldn't come far as what i got was always far from the real solution. $$ x=ce^{-t}-2t+2 \\\ y=c(1+t)e^{-t}-t^2+2$$ How sound i approach such problems?
Edit: I am looking at functions $x$ and $y$ as on two parametric function. So they are functions of parameter $t$. I want to find some interdependece between them and possibly some derivatives. Both $x$ and $y$ are dependant on $C$, which is a constant. The final equation should be without it.
Shortly, I am looking for a differential equation that those functions solve.
I tried with something like $ \frac{dy}{dx} = \frac{dy}{dt} \frac{dt}{dx}$, but I didn't get any good results.

Answer 1

This is not an answer but a comment too long to be edited in the comments section.

$$ x=ce^{-t}-2t+2 \tag 1$$ $$y=c(1+t)e^{-t}-t^2+2 \tag 2$$

I agree with the Ted Shifrin's comment. Supposing that the problem is to eliminate $c$ and $t$ in order to get a differential equation involving only $x,y,\frac{dy}{dx},\frac{d^2y}{dx^2},...$ , they are an infinity of possible answers depending on the kind of differential equation and the order expected.

For example, for a first order nonlinear differential equation :

Take $ce^{-t}$ from $(1)$ and put it into $(2)$ $$y=(1+t)(x+2t-2)-t^2+2 \tag 3$$ Differentiate $(1)$ and $(2)$ $$\begin{cases} \frac{dx}{dt}=-ce^{-t}-2 \\ \frac{dy}{dt}=-ce^{-t}t-2t\end{cases}\quad\implies\quad \frac{dy}{dx}=t \tag 4$$ Putting $t=y'=\frac{dy}{dx}$ from $(4)$ into $(3)$ gives the ODE : $$y=(1+y')(x+2y'-2)-y'^2+2$$ But probably this is not what the question is asking for. The question should be clarified.