So in my text book(online) we have this question and I'm very lost what to do as my answer is wrong.
The region bounded by the curve $y=x^2$ and the x-axis between $x = 1$ and $x = 0$ is revolved around the line $y = 1$ . Find the volume of this solid of revolution.
What I got was: $$\pi\cdot\int_0^1\left(1-\sqrt{y}\right)^2dy$$
Though it says its wrong.