I am a bit confused on where to start with this one. The question given was
Let $G$ be a non abelian finite group. Prove $|Z(G)| \leq \frac {1}{4} |G|$.
Am I supposed to use some property of centers or am I just blanking on something really basic
2026-04-02 15:54:17.1775145257
Given a finite non abelian group G, prove the order of the center is less than or equal to 1/4 of the order of the group.
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Hint: If $G/Z(G)$ is cyclic, then $G$ is abelian.