Given that $\log_a(b)=1.26$, where $a, b>0, a≠1$, find the value of $\log_a(\sqrt[3] b)$, to the nearest hundredth

Question

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If $\log_a(b)=1.26$, where $a$, $b>0$, $a≠1$, then what is the value of $\log_a(\sqrt[3] b)$, to the nearest hundredth?

Answer 1

if $$log_a(b)=1.26$$ then $$log_a(b^{1/3})=log_a(b)/3=1.26/3=0.42$$