Assuming that "keeping all constant" means $b$, $c$ and $d$ don't change, the new value of $x$ is
$$
x' = 1.05a + b + c + d = 0.05a + x
$$
so
$$
\frac{x'}{x} = \frac{0.05a}{x} + 1
$$
so the relative increase in $x$ is $\frac{0.05a}{x}$,
which you can write as a percent.
Intuitively, the change in $x$ caused by a change in $a$ is reduced by the fraction $a$ contributes to $x$.
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It cannot be known. You have that $x=a+b+c+d$ and wonder about how much bigger $x^\prime=1.05 a + b+c+d$ is. The change in $x$ is $\Delta x=x^\prime-x=0.05a$, but the percentage increase in $x$ is
Assuming that "keeping all constant" means $b$, $c$ and $d$ don't change, the new value of $x$ is $$ x' = 1.05a + b + c + d = 0.05a + x $$ so $$ \frac{x'}{x} = \frac{0.05a}{x} + 1 $$ so the relative increase in $x$ is $\frac{0.05a}{x}$, which you can write as a percent.
Intuitively, the change in $x$ caused by a change in $a$ is reduced by the fraction $a$ contributes to $x$.