Given two circles, prove the following

Question

See picture

I was able to identify the cyclic quadrilateral that exists, but not sure how to prove this using that information

Answer 1

Hint: There's not just one, but two, cyclic quadrilaterals. Draw the line $AB$.

Answer 2

$\angle QPA=\pi-\angle ABQ=\angle ABS=\pi-\angle ARS=>PQ \;||\;RS\\\text{Q.E.D.}$