When finding a surface integral you first must parametrise the surface into $r = r(u,v)$. So the area element is a function of $u$ and $v$. Does that mean that grad of it is zero? That is, is $$\nabla . dS = 0?$$
2026-03-30 14:27:18.1774880838
Gradient of surface area element $\nabla . dS$
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