Handling opposites when adding and subtracting rational expressions

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I'm following example 8.47 from the OpenStax book Elementary Algebra.

When trying to create a common denominator it is sometimes necessary to handle opposites on either side of an equation.

In the example, $(2-n)$ needs to be converted to $(n-2)$ as follows:

$$-\frac{(n+3)}{(2-n)}$$

To do this we multiply the numerator and denominator by $-1$.

$$-\frac{(-1)(n+3)}{(-1)(2-n)}$$

Which gives:

$$+\frac{(n+3)}{(n-2)}$$

I understand why the denominator changes but not why the numerator stays the same and the sign of the whole expression changes. Could someone explain this, please?

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Don't forget the minus sign 'outside' the fraction disappeared as well:

$$-\frac{(-1)(n+3)}{(-1)(2-n)}=$$ $$-1\frac{(-1)(n+3)}{(-1)(2-n)}=$$ $$\frac{-1\cdot-1\cdot(n+3)}{(-1)(2-n)}=$$ $$\frac{(n+3)}{(-1)(2-n)}=$$ $$\frac{(n+3)}{(n-2)}$$