Question

Galois group of $T^3-2$ over $ \mathbb{F}_5$

score 79 · Answer 1 · 2026-03-26 12:36:31

79

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Galois group of $T^3-2$ over $ \mathbb{F}_5$

Published on 26 Mar 2026 - 12:36

score 118 · Answer 2 · 2026-04-09 00:33:34

118

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Suppose$f:S_{3}\longrightarrow R^{\ast}$is Homomorphism.Then Kernal of h has

Published on 09 Apr 2026 - 0:33

score 54 · Answer 3 · 2018-02-02 08:24:29

54

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Find the order of $(3,1)+\langle0,2\rangle$ in $ \Bbb Z_{4}\oplus \Bbb Z_{8}/\langle0,2\rangle$

Published on 02 Feb 2018 - 8:24

score 461 · Answer 4 · 2026-04-13 10:00:24

461

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Finite set of generators of monomial ideal form Gröbner basis

Published on 13 Apr 2026 - 10:00

score 218 · Answer 5 · 2026-04-09 00:11:46

218

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Proof about Hyperabelian Groups

Published on 09 Apr 2026 - 0:11

score 61 · Answer 6 · 2026-03-25 12:29:23

61

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Show this is contradictory: $\frac12 sin(2t) \equiv b_1cos(t)+...+b_kcos(kt)+c_1sin(t)+...c_lsin(lt)$ where $b_1,...,b_k,c_1,...,c_l\in \mathbb Z$

Published on 25 Mar 2026 - 12:29

score 91 · Answer 7 · 2026-04-09 03:42:07

91

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Prove $\langle x \rangle + \cap P_i = \cap (\langle x \rangle + P_i)$ for monomials ideals.

Published on 09 Apr 2026 - 3:42

score 236 · Answer 8 · 2026-04-08 22:44:37

236

Views

Example of a module that is finitely generated, finitely cogenerated and linearly compact, but not Artinian!

Published on 08 Apr 2026 - 22:44

score 349 · Answer 9 · 2026-04-09 00:05:18

349

Views

The reduced basis for a binomial ideal is formed by binomials

Published on 09 Apr 2026 - 0:05

score 284 · Answer 10 · 2026-04-11 00:36:10

284

Views

Stabilizer of $1$ on $S_6$

Published on 11 Apr 2026 - 0:36

score 61 · Answer 11 · 2026-04-09 00:04:12

61

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Verma module $V(\lambda)$ of $U_q(\mathfrak{sl}_2)$ is not simple $\implies$ $\lambda = \pm q^n$

Published on 09 Apr 2026 - 0:04

score 26 · Answer 12 · 2026-04-13 02:32:30

26

Views

Checking defining relation on a basis

Published on 13 Apr 2026 - 2:32

score 75 · Answer 13 · 2026-04-12 21:10:52

75

Views

If $H_{3}$ is subgroup of $G$ that satisfies $H_3 \subseteq H_1 \cup H_2$ and $H_3 \not\subset H_2$, then $H_3 \subseteq H_1$.

Published on 12 Apr 2026 - 21:10

score 554 · Answer 14 · 2026-04-09 00:05:55

554

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Second part of Sylow's Theorem about conjugacy

Published on 09 Apr 2026 - 0:05

score 113 · Answer 15 · 2026-04-10 01:40:55

113

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$n$-fold product is a morphism of coalgebras

Published on 10 Apr 2026 - 1:40

List Question

Galois group of $T^3-2$ over $ \mathbb{F}_5$

Suppose$f:S_{3}\longrightarrow R^{\ast}$is Homomorphism.Then Kernal of h has

Find the order of $(3,1)+\langle0,2\rangle$ in $ \Bbb Z_{4}\oplus \Bbb Z_{8}/\langle0,2\rangle$

Finite set of generators of monomial ideal form Gröbner basis

Proof about Hyperabelian Groups

Show this is contradictory: $\frac12 sin(2t) \equiv b_1cos(t)+...+b_kcos(kt)+c_1sin(t)+...c_lsin(lt)$ where $b_1,...,b_k,c_1,...,c_l\in \mathbb Z$

Prove $\langle x \rangle + \cap P_i = \cap (\langle x \rangle + P_i)$ for monomials ideals.

Example of a module that is finitely generated, finitely cogenerated and linearly compact, but not Artinian!

The reduced basis for a binomial ideal is formed by binomials

Stabilizer of $1$ on $S_6$

Verma module $V(\lambda)$ of $U_q(\mathfrak{sl}_2)$ is not simple $\implies$ $\lambda = \pm q^n$

Checking defining relation on a basis

If $H_{3}$ is subgroup of $G$ that satisfies $H_3 \subseteq H_1 \cup H_2$ and $H_3 \not\subset H_2$, then $H_3 \subseteq H_1$.

Second part of Sylow's Theorem about conjugacy

$n$-fold product is a morphism of coalgebras

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