Question

Proving Zermelo's Theorem implies the Axiom of Choice

score 437 · Answer 1 · 2013-09-30 11:33:07

437

Views

Proving Zermelo's Theorem implies the Axiom of Choice

Published on 30 Sep 2013 - 11:33

score 344 · Answer 2 · 2013-10-02 12:18:25

344

Views

Why is the measure of the reals not zero?

Published on 02 Oct 2013 - 12:18

score 690 · Answer 3 · 2013-10-03 08:29:11

690

Views

Proving that without the axiom of choice there is a set with an accumulation point that isn'tthe limit of a convergeant sequence

Published on 03 Oct 2013 - 8:29

score 931 · Answer 4 · 2013-10-08 21:24:26

931

Views

Boolean prime ideal theorem and the axiom of choice

Published on 08 Oct 2013 - 21:24

score 1.5k · Answer 5 · 2026-03-27 02:33:15

1.5k

Views

Well-ordering theorem and second-order logic

Published on 27 Mar 2026 - 2:33

score 565 · Answer 6 · 2013-10-23 21:40:38

565

Views

Axiom of countable choice

Published on 23 Oct 2013 - 21:40

score 98 · Answer 7 · 2013-10-24 15:36:44

98

Views

Do we need the axiom of choice in here?

Published on 24 Oct 2013 - 15:36

score 462 · Answer 8 · 2013-10-25 20:11:20

462

Views

Inductive definition with choice for sequence

Published on 25 Oct 2013 - 20:11

score 153 · Answer 9 · 2013-10-26 02:16:37

153

Views

Extending a Filter in a Well-Ordered Boolean Algebra to an Ultrafilter WITHOUT the Axiom of Choice

Published on 26 Oct 2013 - 2:16

score 311 · Answer 10 · 2013-10-29 01:32:12

311

Views

Relative Consistency proof for the Axiom of Choice

Published on 29 Oct 2013 - 1:32

score 222 · Answer 11 · 2013-10-29 05:30:40

222

Views

The union of a countable set of countable sets is countable

Published on 29 Oct 2013 - 5:30

score 761 · Answer 12 · 2013-11-10 02:14:39

761

Views

Can we prove that every ordered space is normal without choice?

Published on 10 Nov 2013 - 2:14

score 363 · Answer 13 · 2026-03-27 10:11:03

363

Views

Can $\mathbb{R}$ be written as an ascending union of proper additive subgroups?

Published on 27 Mar 2026 - 10:11

score 145 · Answer 14 · 2013-11-13 19:46:15

145

Views

Does the dualizing process on vector spaces necessarily terminate?

Published on 13 Nov 2013 - 19:46

score 671 · Answer 15 · 2013-11-14 11:02:30

671

Views

Can Tarski's circle squaring problem be solved with measurable sets and/or without the Axiom of Choice?

Published on 14 Nov 2013 - 11:02

List Question

Proving Zermelo's Theorem implies the Axiom of Choice

Why is the measure of the reals not zero?

Proving that without the axiom of choice there is a set with an accumulation point that isn'tthe limit of a convergeant sequence

Boolean prime ideal theorem and the axiom of choice

Well-ordering theorem and second-order logic

Axiom of countable choice

Do we need the axiom of choice in here?

Inductive definition with choice for sequence

Extending a Filter in a Well-Ordered Boolean Algebra to an Ultrafilter WITHOUT the Axiom of Choice

Relative Consistency proof for the Axiom of Choice

The union of a countable set of countable sets is countable

Can we prove that every ordered space is normal without choice?

Can $\mathbb{R}$ be written as an ascending union of proper additive subgroups?

Does the dualizing process on vector spaces necessarily terminate?

Can Tarski's circle squaring problem be solved with measurable sets and/or without the Axiom of Choice?

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