Question

If $K$ is $w$−compact and convex, $f\in X^\ast \implies f$ attains its maximum on $K$

score 61 · Answer 1 · 2026-04-12 17:36:04

61

Views

If $K$ is $w$−compact and convex, $f\in X^\ast \implies f$ attains its maximum on $K$

Published on 12 Apr 2026 - 17:36

score 180 · Answer 2 · 2026-04-10 22:35:30

180

Views

What is the relationship between convergence uniformly, pointwisely, weakly, in $L^{\infty}$ norm and in $L^{p} $ norm?

Published on 10 Apr 2026 - 22:35

score 120 · Answer 3 · 2026-04-09 23:30:06

120

Views

A trouble about the Ekeland variational principle

Published on 09 Apr 2026 - 23:30

score 602 · Answer 4 · 2026-04-15 13:51:51

602

Views

Isometry on a dense sub-space of a Banach space?

Published on 15 Apr 2026 - 13:51

score 65 · Answer 5 · 2026-04-15 20:09:51

65

Views

A metric space $(\Bbb R,d)$ with $d(x,y)=||x-y||$ is complete!

Published on 15 Apr 2026 - 20:09

score 272 · Answer 6 · 2026-04-12 01:44:14

272

Views

A trouble about the Simons’ inequality

Published on 12 Apr 2026 - 1:44

score 91 · Answer 7 · 2026-04-17 04:38:08

91

Views

$F_N(t)=\int_{-1/N}^0\overline{f}(t+h)dh$ implies $\|F_N\|_{L^2((0,T); X)}\leq\|f\|_{L^2((0,T); X)}$?

Published on 17 Apr 2026 - 4:38

score 140 · Answer 8 · 2026-04-11 03:35:10

140

Views

Contraction Mappings

Published on 11 Apr 2026 - 3:35

score 429 · Answer 9 · 2026-04-12 08:52:59

429

Views

Is there a noncompact operator from $\ell^\infty$ to a reflexive space?

Published on 12 Apr 2026 - 8:52

score 6.5k · Answer 10 · 2026-04-15 02:07:52

6.5k

Views

equivalent norms in Banach spaces of infinite dimension

Published on 15 Apr 2026 - 2:07

score 1.2k · Answer 11 · 2026-04-16 13:38:08

1.2k

Views

Sequences are Cauchy depending on the norm?

Published on 16 Apr 2026 - 13:38

score 83 · Answer 12 · 2026-04-13 20:55:42

83

Views

If $(M_{\lambda})$ be a chain of closed affine subspaces of $X$ $\Longrightarrow$ $\displaystyle \bigcap_{\lambda\in L} M_{\lambda}\neq \emptyset \;$?

Published on 13 Apr 2026 - 20:55

score 1.6k · Answer 13 · 2026-04-09 12:54:22

1.6k

Views

A relatively bounded perturbation of a closed operator is a closed operator.

Published on 09 Apr 2026 - 12:54

score 635 · Answer 14 · 2026-04-17 12:03:07

635

Views

Resolvent lemma

Published on 17 Apr 2026 - 12:03

score 170 · Answer 15 · 2026-04-13 23:13:45

170

Views

The topology on bounded sets in $X$** of pointwise convergence on $B$ is metrizable

Published on 13 Apr 2026 - 23:13

List Question

If $K$ is $w$−compact and convex, $f\in X^\ast \implies f$ attains its maximum on $K$

What is the relationship between convergence uniformly, pointwisely, weakly, in $L^{\infty}$ norm and in $L^{p} $ norm?

A trouble about the Ekeland variational principle

Isometry on a dense sub-space of a Banach space?

A metric space $(\Bbb R,d)$ with $d(x,y)=||x-y||$ is complete!

A trouble about the Simons’ inequality

$F_N(t)=\int_{-1/N}^0\overline{f}(t+h)dh$ implies $\|F_N\|_{L^2((0,T); X)}\leq\|f\|_{L^2((0,T); X)}$?

Contraction Mappings

Is there a noncompact operator from $\ell^\infty$ to a reflexive space?

equivalent norms in Banach spaces of infinite dimension

Sequences are Cauchy depending on the norm?

If $(M_{\lambda})$ be a chain of closed affine subspaces of $X$ $\Longrightarrow$ $\displaystyle \bigcap_{\lambda\in L} M_{\lambda}\neq \emptyset \;$?

A relatively bounded perturbation of a closed operator is a closed operator.

Resolvent lemma

The topology on bounded sets in $X$** of pointwise convergence on $B$ is metrizable

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