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15
Math.TechQA.Club
2014-12-21 15:09:46
206
Views
Binomial-coefficients if, k, m, n natural numbers and k \leq n the result of
Published on
21 Dec 2014 - 15:09
#combinatorics
#binomial-coefficients
97
Views
If $k, m, n$, are natural numbers and $k \leq n$ What is the final answer of this :
Published on
29 Mar 2026 - 10:08
#combinatorics
#binomial-coefficients
#binomial-theorem
69
Views
Congruence with binomial
Published on
26 Mar 2026 - 17:28
#number-theory
#modular-arithmetic
#binomial-coefficients
#congruences
431
Views
How to prove that the sum of squared binomials equals $\binom{2n}{n}$
Published on
22 Dec 2014 - 19:45
#summation
#induction
#binomial-coefficients
485
Views
Binomial theorem.
Published on
23 Dec 2014 - 18:35
#calculus
#sequences-and-series
#combinatorics
#binomial-coefficients
80
Views
expressing canonical base of univariate polynomials in binomial base
Published on
24 Dec 2014 - 8:35
#linear-algebra
#polynomials
#binomial-coefficients
129
Views
Asymptotics of integer compositions
Published on
24 Dec 2014 - 10:54
#combinatorics
#summation
#binomial-coefficients
174
Views
An identity involving partial fractions decompositions
Published on
27 Mar 2026 - 1:44
#summation
#binomial-coefficients
#partial-fractions
485
Views
Good approximation for $\binom{N}{\frac{N}{2}}$
Published on
30 Mar 2026 - 9:29
#binomial-coefficients
#approximation
478
Views
What is the value of $\sum_{n=0}^{\infty}(-\frac{1}{8})^n\binom{2n}{n}$
Published on
25 Dec 2014 - 14:57
#sequences-and-series
#binomial-coefficients
81
Views
If a word appears with probability $0.05$, how many words are needed so that it appears with probability $0.99$?
Published on
25 Dec 2014 - 23:29
#probability
#binomial-coefficients
627
Views
How to compute $\sum^n_{k=0}(-1)^k\binom{n}{k}k^n$
Published on
26 Dec 2014 - 4:19
#summation
#binomial-coefficients
1.3k
Views
Xmas Maths 2014
Published on
03 Apr 2026 - 1:41
#combinatorics
#summation
#binomial-coefficients
#recreational-mathematics
1.3k
Views
Combinatoric proof for $\sum_{k=0}^n{n\choose k}\left(-1\right)^k\left(n-k\right)^4 = 0$ ($n\geqslant5$)
Published on
26 Mar 2026 - 11:18
#combinatorics
#binomial-coefficients
#binomial-theorem
#combinatorial-proofs
356
Views
Is there a "counting groups/committees" proof for the identity $\binom{\binom{n}{2}}{2}=3\binom{n+1}{4}$?
Published on
26 Mar 2026 - 11:17
#combinatorics
#binomial-coefficients
#combinatorial-proofs
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