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15
Math.TechQA.Club
2026-03-27 23:35:51
87
Views
Is there some way to prove $n\binom nr=(r+1)\binom n{r+1}+r\binom nr$ using generating functions?
Published on
27 Mar 2026 - 23:35
#combinatorics
#binomial-coefficients
#generating-functions
129
Views
Sum involving binomial coefficients and falling factorials
Published on
15 Jan 2019 - 3:15
#summation
#binomial-coefficients
274
Views
Binomial sum which adds to $2^n n!$
Published on
25 Mar 2026 - 20:52
#combinatorics
#binomial-coefficients
#combinatorial-proofs
423
Views
Find the sum $S=\sum\limits_{k=1}^{n} {4k-1 \choose k}$
Published on
16 Jan 2019 - 5:26
#combinatorics
#algebra-precalculus
#summation
#binomial-coefficients
473
Views
Summation of: (binomial coefficients * Stirling numbers of the second kind)
Published on
26 Mar 2026 - 12:37
#combinatorics
#binomial-coefficients
#stirling-numbers
30
Views
Analytical form of the binomial moments
Published on
17 Jan 2019 - 16:07
#combinatorics
#summation
#binomial-coefficients
329
Views
Prove for any positive integer $n$, $(4n)!$ is divisible by $2^{3n}\cdot 3^n$
Published on
27 Mar 2026 - 13:27
#combinatorics
#elementary-number-theory
#discrete-mathematics
#binomial-coefficients
#divisibility
177
Views
Finding determinant of matrix involving binomial coefficients
Published on
17 Jan 2019 - 18:59
#linear-algebra
#binomial-coefficients
#determinant
183
Views
Summation of Stirling numbers of second kind
Published on
26 Mar 2026 - 12:36
#combinatorics
#binomial-coefficients
#stirling-numbers
302
Views
Evaluate $4^n = \sum_{k=0}^{n} {n \choose k} 3^k$
Published on
25 Mar 2026 - 20:52
#combinatorics
#binomial-coefficients
#combinations
#combinatorial-proofs
241
Views
Lucas number identity
Published on
25 Mar 2026 - 20:24
#discrete-mathematics
#binomial-coefficients
#lucas-numbers
52
Views
Summation using binomial theorem
Published on
27 Mar 2026 - 10:30
#summation
#binomial-coefficients
#binomial-theorem
424
Views
Closed form for product of Stirling numbers of the second kind
Published on
26 Mar 2026 - 12:37
#combinatorics
#power-series
#binomial-coefficients
#stirling-numbers
532
Views
Closed form expression for the harmonic sum $\sum\limits_{n=1}^{\infty}\frac{H_{2n}}{n^2\cdot4^n}{2n \choose n}$
Published on
25 Mar 2026 - 9:28
#real-analysis
#sequences-and-series
#definite-integrals
#binomial-coefficients
#harmonic-numbers
152
Views
How to prove combinatorial $\sum_{k=0}^{n/2} {n\choose2k} = \sum_{k=0}^{n/2 - 1} {n\choose2k+1} = 2^{n-1}$
Published on
24 Jan 2019 - 11:04
#combinatorics
#summation
#binomial-coefficients
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