Question

Why is it not possible to calculate the amount of combinations for a byte using the Binomial coefficient

score 95 · Answer 1 · 2019-05-16 12:06:30

95

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Why is it not possible to calculate the amount of combinations for a byte using the Binomial coefficient

Published on 16 May 2019 - 12:06

score 609 · Answer 2 · 2019-05-16 21:47:18

609

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Binomial coefficients with variable in exponent

Published on 16 May 2019 - 21:47

score 99 · Answer 3 · 2019-05-16 21:50:20

99

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What is the coefficient of $x^5$ in $(1+x+x^2+x^3+x^4+x^5)^{17}$?

Published on 16 May 2019 - 21:50

score 1.6k · Answer 4 · 2026-03-27 20:21:04

1.6k

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Proving that $\sum_{k=0}^{2n} {2k \choose k } {2n \choose k}\left( \frac{-1}{2} \right)^k=4^{-n}~{2n \choose n}.$

Published on 27 Mar 2026 - 20:21

score 41 · Answer 5 · 2026-03-25 11:11:56

41

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Case $Sym^n(K^m)\cong K^6$ for $(m,n)$

Published on 25 Mar 2026 - 11:11

score 1.1k · Answer 6 · 2019-05-17 21:55:54

1.1k

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What's the probability that in a box of a dozen donuts with flavors randomly picked out of 14 no more than 3 flavors are in the box? (Check my work)

Published on 17 May 2019 - 21:55

score 67 · Answer 7 · 2026-03-26 04:35:13

67

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Limit of $\sum_{r=0}^{n}\frac{{n\choose r}}{n^r\cdot(r+3)}$ as $n\rightarrow\infty$

Published on 26 Mar 2026 - 4:35

score 66 · Answer 8 · 2026-03-27 20:14:26

66

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How is $\sum_{k=0}^{5} {}^5C_k\sin(kx)\cos(5-k)x=16\sin(5x)$?

Published on 27 Mar 2026 - 20:14

score 53 · Answer 9 · 2019-05-18 20:55:55

53

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Find $\sum_{k = 0}^{11} \frac{1}{k+1}\binom{11}{k}$

Published on 18 May 2019 - 20:55

score 88 · Answer 10 · 2019-05-19 03:26:16

88

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A polynomial coefficient

Published on 19 May 2019 - 3:26

score 342 · Answer 11 · 2026-03-26 06:17:45

342

Views

Expected Hamming distance between typical strings

Published on 26 Mar 2026 - 6:17

score 394 · Answer 12 · 2026-03-25 16:06:41

394

Views

A "binomial" generalization of harmonic numbers

Published on 25 Mar 2026 - 16:06

score 132 · Answer 13 · 2026-03-25 12:38:54

132

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How do I produce a Bézier curve with 4 points and without just using a website?

Published on 25 Mar 2026 - 12:38

score 353 · Answer 14 · 2019-05-20 10:40:58

353

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Double Binomial coefficient sum identity $S = \sum_{k = 0}^{n} (-1)^k {{4n-1-2k}\choose{2n-2k}}{{2n-1}\choose{k}}$

Published on 20 May 2019 - 10:40

score 388 · Answer 15 · 2019-05-20 15:10:51

388

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Simplification of binomial coefficient

Published on 20 May 2019 - 15:10

List Question

Why is it not possible to calculate the amount of combinations for a byte using the Binomial coefficient

Binomial coefficients with variable in exponent

What is the coefficient of $x^5$ in $(1+x+x^2+x^3+x^4+x^5)^{17}$?

Proving that $\sum_{k=0}^{2n} {2k \choose k } {2n \choose k}\left( \frac{-1}{2} \right)^k=4^{-n}~{2n \choose n}.$

Case $Sym^n(K^m)\cong K^6$ for $(m,n)$

What's the probability that in a box of a dozen donuts with flavors randomly picked out of 14 no more than 3 flavors are in the box? (Check my work)

Limit of $\sum_{r=0}^{n}\frac{{n\choose r}}{n^r\cdot(r+3)}$ as $n\rightarrow\infty$

How is $\sum_{k=0}^{5} {}^5C_k\sin(kx)\cos(5-k)x=16\sin(5x)$?

Find $\sum_{k = 0}^{11} \frac{1}{k+1}\binom{11}{k}$

A polynomial coefficient

Expected Hamming distance between typical strings

A "binomial" generalization of harmonic numbers

How do I produce a Bézier curve with 4 points and without just using a website?

Double Binomial coefficient sum identity $S = \sum_{k = 0}^{n} (-1)^k {{4n-1-2k}\choose{2n-2k}}{{2n-1}\choose{k}}$

Simplification of binomial coefficient

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