List questions from binomial-theorem

Published on 07 Sep 2013 - 19:03

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Binomial expansion of modulus?

Published on 07 Sep 2013 - 20:17

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Finding the last two digits of a number by binomial theorem

Published on 28 Mar 2026 - 9:55

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General method to solve Combination problems based on binomial series.

Published on 12 Sep 2013 - 17:34

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How to determine the number of terms in $(x+\frac{1}{x}+1)^n$

Published on 13 Sep 2013 - 12:44

265

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How would I go about showing $\cos(x+\frac{\pi}{2})=-\sin(x)$?

Published on 14 Sep 2013 - 23:39

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Strange Binomial question.

Published on 15 Sep 2013 - 10:13

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Trying to prove this using induction hypothesis

Published on 03 Apr 2026 - 3:15

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Need help showing $\mathbb E(5^x) = (1+4p)^n$

Published on 24 Sep 2013 - 23:16

117

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Related Theorem of Binomial Theorem

Published on 25 Sep 2013 - 1:11

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Another binomial identity

Published on 26 Sep 2013 - 19:36

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How to perform a binomial expansion on $m*v^2$?

Published on 29 Sep 2013 - 1:26

253

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Help with binomial coefficients using binomial theorem

Published on 29 Sep 2013 - 18:46

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confidence interval of binomial disribution using standard deviation

Published on 31 Mar 2026 - 17:32

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Further simplify this: $\sum\limits_{k=0}^{n}{n\choose k}\cdot a^k\cdot b^{n-k}\cdot \frac{1}{(k+1)^2}$

Published on 12 Oct 2013 - 3:27

List Question

Generating Functions in Discrete Mathematics in Computer Science

Binomial expansion of modulus?

Finding the last two digits of a number by binomial theorem

General method to solve Combination problems based on binomial series.

How to determine the number of terms in $(x+\frac{1}{x}+1)^n$

How would I go about showing $\cos(x+\frac{\pi}{2})=-\sin(x)$?

Strange Binomial question.

Trying to prove this using induction hypothesis

Need help showing $\mathbb E(5^x) = (1+4p)^n$

Related Theorem of Binomial Theorem

Another binomial identity

How to perform a binomial expansion on $m*v^2$?

Help with binomial coefficients using binomial theorem

confidence interval of binomial disribution using standard deviation

Further simplify this: $\sum\limits_{k=0}^{n}{n\choose k}\cdot a^k\cdot b^{n-k}\cdot \frac{1}{(k+1)^2}$

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