List questions from binomial-theorem

Published on 16 Apr 2026 - 21:06

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Expansion of $(a+b)^{1/3}$ with binomial theorem

Published on 16 Apr 2026 - 2:04

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Complex Numbers Binomial Expansion Proof

Published on 12 Apr 2026 - 5:49

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Simplifying nested radicals? $\left(\sqrt{4+\sqrt{16-a^2}}+\sqrt{4-\sqrt{16-a^2}}\right)^2$

Published on 29 Apr 2026 - 14:09

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The least upper bound for $\frac{\sum_{i=0}^m{\binom{m}{i}x^i}}{\sum_{i=0}^{m}{x^i}}$

Published on 10 May 2026 - 14:07

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Approximation Binomial theorem "Again 2"

Published on 29 Apr 2026 - 12:23

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How to add this combinations? PLEASE HELP

Published on 06 Apr 2026 - 4:05

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Negative binomial expansion problem

Published on 29 Apr 2026 - 12:23

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Sequences; the binomial theorem

Published on 16 Apr 2026 - 4:04

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how decomposition this formula

Published on 08 Apr 2026 - 15:49

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Summation of binomial coefficients up to $r$ terms.

Published on 25 Mar 2026 - 12:53

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How do we show that $(2k+1)^{2n} \bmod 4 = 1$?

Published on 13 Apr 2026 - 21:58

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If the total number of terms in the expansion of $(a-b+2c)^n=45$, then $n=?$

Published on 15 Apr 2026 - 12:12

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How to find coefficient of multiple binomial expansions quickly?

Published on 25 Mar 2026 - 15:59

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Prove $2 \cdot \sum\limits_{k = 0}^{n} \binom{2n}{2k} = 2^{2n}$ without induction

Published on 25 Mar 2026 - 16:00

List Question

Proving Taylor's expansion of sin x

Expansion of $(a+b)^{1/3}$ with binomial theorem

Complex Numbers Binomial Expansion Proof

Simplifying nested radicals? $\left(\sqrt{4+\sqrt{16-a^2}}+\sqrt{4-\sqrt{16-a^2}}\right)^2$

The least upper bound for $\frac{\sum_{i=0}^m{\binom{m}{i}x^i}}{\sum_{i=0}^{m}{x^i}}$

Approximation Binomial theorem "Again 2"

How to add this combinations? PLEASE HELP

Negative binomial expansion problem

Sequences; the binomial theorem

how decomposition this formula

Summation of binomial coefficients up to $r$ terms.

How do we show that $(2k+1)^{2n} \bmod 4 = 1$?

If the total number of terms in the expansion of $(a-b+2c)^n=45$, then $n=?$

How to find coefficient of multiple binomial expansions quickly?

Prove $2 \cdot \sum\limits_{k = 0}^{n} \binom{2n}{2k} = 2^{2n}$ without induction

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