Question

Modular Arithmetic CRT: How do modulo with very big numbers

score 1.3k · Answer 1 · 2019-08-24 17:27:52

1.3k

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Modular Arithmetic CRT: How do modulo with very big numbers

Published on 24 Aug 2019 - 17:27

score 1k · Answer 2 · 2019-08-27 16:17:09

1k

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From Fermat's Theorem to The Chinese Remainder Theorem

Published on 27 Aug 2019 - 16:17

score 171 · Answer 3 · 2026-03-25 04:39:33

171

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Why is adelic approximation a generalisation of Chinese remainder theorem?

Published on 25 Mar 2026 - 4:39

score 71 · Answer 4 · 2019-09-05 17:46:22

71

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Batching items using Chinese Remainder Theorem

Published on 05 Sep 2019 - 17:46

score 37 · Answer 5 · 2019-09-11 03:01:26

37

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Ensuring a specific solution between two moduli

Published on 11 Sep 2019 - 3:01

score 83 · Answer 6 · 2019-09-11 08:47:01

83

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Chinese Remainder Theorem to find possible element

Published on 11 Sep 2019 - 8:47

score 395 · Answer 7 · 2019-09-12 14:32:08

395

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Find all $x\in \mathbb{Z}$ with $x \equiv 2 \mod 4$ , $x \equiv 8\mod9$ and $x \equiv 1\mod5$

Published on 12 Sep 2019 - 14:32

score 185 · Answer 8 · 2019-09-20 17:42:49

185

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$ab+ac+bc \equiv 1 \bmod abc$ or "easy chinese remainder theorem problems"

Published on 20 Sep 2019 - 17:42

score 298 · Answer 9 · 2019-09-30 15:09:41

298

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Prove that for every natural number $n$, there is a set $S$ of $n$ natural numbers such that for any two different numbers $a,b$ From $S$ the number…

Published on 30 Sep 2019 - 15:09

score 1k · Answer 10 · 2026-03-25 13:55:11

1k

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How can I get the smallest possible answer with the Chinese Remainder Theorem?

Published on 25 Mar 2026 - 13:55

score 235 · Answer 11 · 2014-03-16 20:37:22

235

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Solve congruence system $\ x\equiv m_i-1 \pmod{m_i}\,$ for $\,i = 1,\ldots, k$

Published on 16 Mar 2014 - 20:37

score 633 · Answer 12 · 2014-03-18 00:00:49

633

Views

Combining results with Chinese Remainder Theorem?

Published on 18 Mar 2014 - 0:00

score 2.9k · Answer 13 · 2014-03-20 03:53:55

Prove that if a, b are relatively prime integers, then $\Bbb{Z}/ab\Bbb{Z}$ is isomorphic to $\mathbb{Z}/a\Bbb{Z} \times \Bbb{Z}/b\Bbb{Z}$.

score 10.9k · Answer 14 · 2014-03-20 05:15:05

10.9k

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Find all solutions, if any, to the system of congruences x ≡ 7 (mod 9), x ≡ 4 (mod 12), and x ≡ 16 (mod 21)

Published on 20 Mar 2014 - 5:15

score 127 · Answer 15 · 2014-03-20 15:22:20

127

Views

Easy linear combinations problem.

Published on 20 Mar 2014 - 15:22

List Question

Modular Arithmetic CRT: How do modulo with very big numbers

From Fermat's Theorem to The Chinese Remainder Theorem

Why is adelic approximation a generalisation of Chinese remainder theorem?

Batching items using Chinese Remainder Theorem

Ensuring a specific solution between two moduli

Chinese Remainder Theorem to find possible element

Find all $x\in \mathbb{Z}$ with $x \equiv 2 \mod 4$ , $x \equiv 8\mod9$ and $x \equiv 1\mod5$

$ab+ac+bc \equiv 1 \bmod abc$ or "easy chinese remainder theorem problems"

Prove that for every natural number $n$, there is a set $S$ of $n$ natural numbers such that for any two different numbers $a,b$ From $S$ the number…

How can I get the smallest possible answer with the Chinese Remainder Theorem?

Solve congruence system $\ x\equiv m_i-1 \pmod{m_i}\,$ for $\,i = 1,\ldots, k$

Combining results with Chinese Remainder Theorem?

Prove that if a, b are relatively prime integers, then $\Bbb{Z}/ab\Bbb{Z}$ is isomorphic to $\mathbb{Z}/a\Bbb{Z} \times \Bbb{Z}/b\Bbb{Z}$.

Find all solutions, if any, to the system of congruences x ≡ 7 (mod 9), x ≡ 4 (mod 12), and x ≡ 16 (mod 21)

Easy linear combinations problem.

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