Question

A (combinatorics?) problem about shoes

score 137 · Answer 1 · 2013-11-16 21:36:33

137

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A (combinatorics?) problem about shoes

Published on 16 Nov 2013 - 21:36

score 260 · Answer 2 · 2013-11-20 16:23:40

260

Views

Proof of combinatorial identity

Published on 20 Nov 2013 - 16:23

score 213 · Answer 3 · 2013-11-28 19:33:14

213

Views

Combinatorial proof with binomial coefficients

Published on 28 Nov 2013 - 19:33

score 344 · Answer 4 · 2013-12-03 23:58:34

344

Views

A congruence in the number of certain ternary strings

Published on 03 Dec 2013 - 23:58

score 115 · Answer 5 · 2013-12-06 07:57:10

115

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Using a combinatorial proof , prove that if n and k are integers with $1\le k \le n$, then $ n\binom {n-1}{k-1} = k \binom nk $

Published on 06 Dec 2013 - 7:57

score 192 · Answer 6 · 2013-12-06 15:55:45

192

Views

Combinatorial proof for $\binom{2n}{2} = 2\binom{n}{2} + n^2$

Published on 06 Dec 2013 - 15:55

score 237 · Answer 7 · 2013-12-08 15:29:06

237

Views

Combinatorial proof for the identity $1 \times 1! + 2 \times 2! + ... + n \times n! = (n + 1)! - 1$

Published on 08 Dec 2013 - 15:29

score 254 · Answer 8 · 2013-12-19 01:02:39

254

Views

Combinatorial Proofs for $n^3-n= 6\binom{n}{2}+ 6\binom{n}{3}$

Published on 19 Dec 2013 - 1:02

score 996 · Answer 9 · 2014-02-05 16:27:44

996

Views

Show that $\sum\limits_{k=0}^n\binom{2n}{2k}^{\!2}-\sum\limits_{k=0}^{n-1}\binom{2n}{2k+1}^{\!2}=(-1)^n\binom{2n}{n}$

Published on 05 Feb 2014 - 16:27

score 1.1k · Answer 10 · 2014-02-12 21:07:44

1.1k

Views

Combinatorial Proof -$\ n \choose r $ = $\frac nr$$\ n-1 \choose r-1$

Published on 12 Feb 2014 - 21:07

score 1.9k · Answer 11 · 2014-02-14 18:35:03

1.9k

Views

Combinatorial Proof - $\ {1 \over n+1} {2n\choose n} = {2n-1\choose n-1} - {2n-1\choose n+1} = {2n\choose n} - {2n\choose n-1}$

Published on 14 Feb 2014 - 18:35

score 313 · Answer 12 · 2014-02-16 13:41:45

313

Views

To provide a combinatorial argument for a combinatorics equality.

Published on 16 Feb 2014 - 13:41

score 2.8k · Answer 13 · 2014-02-16 18:03:10

2.8k

Views

Prove that $(n!)^2$ is greater than $n^n$ for all values of n greater than 2.

Published on 16 Feb 2014 - 18:03

score 843 · Answer 14 · 2014-02-20 00:14:51

843

Views

Combinatorial proofs of the identity $(a+b)^2 = a^2 +b^2 +2ab$

Published on 20 Feb 2014 - 0:14

score 112 · Answer 15 · 2014-02-20 20:30:19

112

Views

Discrete Mathematics Proof odd degree

Published on 20 Feb 2014 - 20:30

List Question

A (combinatorics?) problem about shoes

Proof of combinatorial identity

Combinatorial proof with binomial coefficients

A congruence in the number of certain ternary strings

Using a combinatorial proof , prove that if n and k are integers with $1\le k \le n$, then $ n\binom {n-1}{k-1} = k \binom nk $

Combinatorial proof for $\binom{2n}{2} = 2\binom{n}{2} + n^2$

Combinatorial proof for the identity $1 \times 1! + 2 \times 2! + ... + n \times n! = (n + 1)! - 1$

Combinatorial Proofs for $n^3-n= 6\binom{n}{2}+ 6\binom{n}{3}$

Show that $\sum\limits_{k=0}^n\binom{2n}{2k}^{\!2}-\sum\limits_{k=0}^{n-1}\binom{2n}{2k+1}^{\!2}=(-1)^n\binom{2n}{n}$

Combinatorial Proof -$\ n \choose r $ = $\frac nr$$\ n-1 \choose r-1$

Combinatorial Proof - $\ {1 \over n+1} {2n\choose n} = {2n-1\choose n-1} - {2n-1\choose n+1} = {2n\choose n} - {2n\choose n-1}$

To provide a combinatorial argument for a combinatorics equality.

Prove that $(n!)^2$ is greater than $n^n$ for all values of n greater than 2.

Combinatorial proofs of the identity $(a+b)^2 = a^2 +b^2 +2ab$

Discrete Mathematics Proof odd degree

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