Question

If $q^k n^2$ is an odd perfect number with Euler prime $q$, which of the following relationships between $q^2$ and $n$ hold?

score 104 · Answer 1 · 2026-03-27 04:03:30

104

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If $q^k n^2$ is an odd perfect number with Euler prime $q$, which of the following relationships between $q^2$ and $n$ hold?

Published on 27 Mar 2026 - 4:03

score 47 · Answer 2 · 2026-03-30 11:59:22

47

Views

Is there a deficient $N$ such that $\sqrt{D(N)} \mid A(N)$ holds, where $D(N)$ is the deficiency and $A(N)$ is the sum of the aliquot parts of $N$?

Published on 30 Mar 2026 - 11:59

score 110 · Answer 3 · 2026-03-26 09:58:11

110

Views

Odd numbers are of form $a+b$ where $a^2+b^2$ is a twin prime

Published on 26 Mar 2026 - 9:58

score 58 · Answer 4 · 2017-09-10 09:52:22

58

Views

If the equation $x^2 = (2^{2^y} + 1)^s + 2^t$ holds, can $t$ be odd?

Published on 10 Sep 2017 - 9:52

score 52 · Answer 5 · 2017-09-10 10:56:14

52

Views

When does $p^s = 2^t + 1$ have a solution, for $t$ odd and $p$ prime?

Published on 10 Sep 2017 - 10:56

score 75 · Answer 6 · 2026-02-23 08:42:02

75

Views

If $F_m = 2^{2^m} + 1$ is prime (with $m \geq 1$), does it follow that $3 \mid \frac{F_m + 1}{2}$?

Published on 23 Feb 2026 - 8:42

score 1.5k · Answer 7 · 2026-03-26 06:19:26

1.5k

Views

How to guess a formula

Published on 26 Mar 2026 - 6:19

score 78 · Answer 8 · 2017-09-13 06:06:43

78

Views

Has this conjecture been discovered before? (Concerns prime numbers and not $\#(n)$ like in a question similar to this)

Published on 13 Sep 2017 - 6:06

score 201 · Answer 9 · 2026-03-29 22:31:42

201

Views

some property of the simple continued fraction for the riemann-zeta function

Published on 29 Mar 2026 - 22:31

score 166 · Answer 10 · 2026-03-26 01:10:31

166

Views

Two new conjectures related to Lemoine's and Goldbach's

Published on 26 Mar 2026 - 1:10

score 679 · Answer 11 · 2017-09-22 00:52:39

679

Views

Does a counterexample always disprove a conjecture?

Published on 22 Sep 2017 - 0:52

score 184 · Answer 12 · 2026-03-29 22:33:55

184

Views

Two equivalent simple continued fractions $A\overset{\color{red}?}=B$

Published on 29 Mar 2026 - 22:33

score 425 · Answer 13 · 2017-09-25 11:22:54

425

Views

A question about Brown Numbers $(m, n) : n! + 1 = m^2$

Published on 25 Sep 2017 - 11:22

score 2.2k · Answer 14 · 2026-03-28 08:42:12

2.2k

Views

An explanation for undergraduated students about why the Jacobian conjecture is hard

Published on 28 Mar 2026 - 8:42

score 97 · Answer 15 · 2026-03-26 01:14:35

97

Views

Feedback on a general conjecture for A = Bp – Cq where p and q are primes?

Published on 26 Mar 2026 - 1:14

List Question

If $q^k n^2$ is an odd perfect number with Euler prime $q$, which of the following relationships between $q^2$ and $n$ hold?

Is there a deficient $N$ such that $\sqrt{D(N)} \mid A(N)$ holds, where $D(N)$ is the deficiency and $A(N)$ is the sum of the aliquot parts of $N$?

Odd numbers are of form $a+b$ where $a^2+b^2$ is a twin prime

If the equation $x^2 = (2^{2^y} + 1)^s + 2^t$ holds, can $t$ be odd?

When does $p^s = 2^t + 1$ have a solution, for $t$ odd and $p$ prime?

If $F_m = 2^{2^m} + 1$ is prime (with $m \geq 1$), does it follow that $3 \mid \frac{F_m + 1}{2}$?

How to guess a formula

Has this conjecture been discovered before? (Concerns prime numbers and not $\#(n)$ like in a question similar to this)

some property of the simple continued fraction for the riemann-zeta function

Two new conjectures related to Lemoine's and Goldbach's

Does a counterexample always disprove a conjecture?

Two equivalent simple continued fractions $A\overset{\color{red}?}=B$

A question about Brown Numbers $(m, n) : n! + 1 = m^2$

An explanation for undergraduated students about why the Jacobian conjecture is hard

Feedback on a general conjecture for A = Bp – Cq where p and q are primes?

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