Question

Compact domain of Lie group path implies existence of a product that is in a neighborhood around the identity

score 19 · Answer 1 · 2026-04-13 13:36:20

19

Views

Compact domain of Lie group path implies existence of a product that is in a neighborhood around the identity

Published on 13 Apr 2026 - 13:36

score 195 · Answer 2 · 2026-05-10 15:40:54

195

Views

Is the set path-connected?

Published on 10 May 2026 - 15:40

score 90 · Answer 3 · 2026-04-16 02:35:21

90

Views

If $(X, d_x)$ and $(Y, d_Y)$ are connected show that $(X \times Y, d)$ where $d((x_1, y_1), (x_2, y_2)) = d_x(x_1, x_2) + d_Y(y_1, y_2)$ is connected

Published on 16 Apr 2026 - 2:35

score 846 · Answer 4 · 2026-05-10 18:01:22

846

Views

How can we check if the set is path-connected?

Published on 10 May 2026 - 18:01

score 183 · Answer 5 · 2026-04-12 17:56:35

183

Views

Check if the set is connected or not

Published on 12 Apr 2026 - 17:56

score 523 · Answer 6 · 2026-04-10 20:25:44

523

Views

Is the unit sphere of $C[0,1]$ connected?

Published on 10 Apr 2026 - 20:25

score 3.1k · Answer 7 · 2026-04-14 10:17:19

3.1k

Views

Homeomorphism preserve compactness and conectedness

Published on 14 Apr 2026 - 10:17

score 122 · Answer 8 · 2026-04-12 23:53:09

122

Views

Closure of Connected Set is Connected

Published on 12 Apr 2026 - 23:53

score 2.4k · Answer 9 · 2026-05-10 15:47:01

2.4k

Views

Proof of Topologist Sine curve is not path connected .

Published on 10 May 2026 - 15:47

score 341 · Answer 10 · 2026-04-12 22:29:52

341

Views

Is connectedness required to show that an analytic function with no zeros in a compact set but constant modulus on the boundary is constant?

Published on 12 Apr 2026 - 22:29

score 514 · Answer 11 · 2026-05-10 18:01:38

514

Views

Open and Connectedness on the Topological Vector Space over $\mathbb{R}$ Implies Path-Connectedness

Published on 10 May 2026 - 18:01

score 511 · Answer 12 · 2026-04-13 06:34:42

511

Views

Is there a continuous and surjective mapping from a simple connected space to the topologist's sine curve?

Published on 13 Apr 2026 - 6:34

score 964 · Answer 13 · 2026-04-15 08:19:12

964

Views

$X$ a compact Hausdorff space and a sequence $A_1 \supset A_2 \supset \dots$ of closed connected subsets. Show that $\bigcap A_n$ is also connected.

Published on 15 Apr 2026 - 8:19

score 603 · Answer 14 · 2026-04-13 11:26:44

603

Views

A disjoint union is not connected.

Published on 13 Apr 2026 - 11:26

score 143 · Answer 15 · 2026-04-14 04:44:31

143

Views

Is the intersection of a component and the boundary of a closed set non-empty?

Published on 14 Apr 2026 - 4:44

List Question

Compact domain of Lie group path implies existence of a product that is in a neighborhood around the identity

Is the set path-connected?

If $(X, d_x)$ and $(Y, d_Y)$ are connected show that $(X \times Y, d)$ where $d((x_1, y_1), (x_2, y_2)) = d_x(x_1, x_2) + d_Y(y_1, y_2)$ is connected

How can we check if the set is path-connected?

Check if the set is connected or not

Is the unit sphere of $C[0,1]$ connected?

Homeomorphism preserve compactness and conectedness

Closure of Connected Set is Connected

Proof of Topologist Sine curve is not path connected .

Is connectedness required to show that an analytic function with no zeros in a compact set but constant modulus on the boundary is constant?

Open and Connectedness on the Topological Vector Space over $\mathbb{R}$ Implies Path-Connectedness

Is there a continuous and surjective mapping from a simple connected space to the topologist's sine curve?

$X$ a compact Hausdorff space and a sequence $A_1 \supset A_2 \supset \dots$ of closed connected subsets. Show that $\bigcap A_n$ is also connected.

A disjoint union is not connected.

Is the intersection of a component and the boundary of a closed set non-empty?

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