Question

Estimation of connected components

score 194 · Answer 1 · 2026-05-06 07:12:37

194

Views

Estimation of connected components

Published on 06 May 2026 - 7:12

score 245 · Answer 2 · 2026-05-05 14:40:34

245

Views

decomposing a graph in connected components

Published on 05 May 2026 - 14:40

score 80 · Answer 3 · 2026-05-07 10:09:52

80

Views

Proving that we can divide a graph to two graphs which induced subgraph is connected on vertices of each one

Published on 07 May 2026 - 10:09

score 74 · Answer 4 · 2026-05-07 10:08:41

74

Views

Does every connected topological space have the property that you can walk around a finite open cover to get from any point to any other?

Published on 07 May 2026 - 10:08

score 115 · Answer 5 · 2026-05-06 09:24:58

115

Views

A set with more than $n$ components has $n+1$ pairwise separated subsets.

Published on 06 May 2026 - 9:24

score 224 · Answer 6 · 2026-05-06 09:32:02

224

Views

Can connectedness preservation be used to define continuity of a function?

Published on 06 May 2026 - 9:32

score 179 · Answer 7 · 2026-05-06 05:23:25

179

Views

Prove the set is not connected

Published on 06 May 2026 - 5:23

score 72 · Answer 8 · 2026-05-05 16:21:08

72

Views

Related the property of two points contained in the same component

Published on 05 May 2026 - 16:21

score 641 · Answer 9 · 2026-05-04 23:12:57

641

Views

Is a connected component a group?

Published on 04 May 2026 - 23:12

score 1.9k · Answer 10 · 2026-05-07 10:09:25

1.9k

Views

f is a continuous function from (X,$\tau$) to {0,1} with discrete topology, if f non constant then (X,$\tau$) disconnected

Published on 07 May 2026 - 10:09

score 63 · Answer 11 · 2026-04-29 12:28:37

63

Views

The separation of the subset $[-1, 0) \cup (0,1)$ in $\mathbb{R}$ contains the limit point of the other

Published on 29 Apr 2026 - 12:28

score 490 · Answer 12 · 2026-05-06 10:00:09

490

Views

Example of a topological space that is connected, not locally connected and not path connected

Published on 06 May 2026 - 10:00

score 77 · Answer 13 · 2026-05-04 04:03:10

77

Views

$f$ has square root if and only if image of $f_*$ contained in $2 \mathbb Z$

Published on 04 May 2026 - 4:03

score 184 · Answer 14 · 2026-05-07 19:46:26

184

Views

Proof explanation to see that subset of $\mathbb{R}^2$ is not path connected.

Published on 07 May 2026 - 19:46

score 70 · Answer 15 · 2026-04-29 12:28:38

70

Views

equivalence of arakelian set definition

Published on 29 Apr 2026 - 12:28

List Question

Estimation of connected components

decomposing a graph in connected components

Proving that we can divide a graph to two graphs which induced subgraph is connected on vertices of each one

Does every connected topological space have the property that you can walk around a finite open cover to get from any point to any other?

A set with more than $n$ components has $n+1$ pairwise separated subsets.

Can connectedness preservation be used to define continuity of a function?

Prove the set is not connected

Related the property of two points contained in the same component

Is a connected component a group?

f is a continuous function from (X,$\tau$) to {0,1} with discrete topology, if f non constant then (X,$\tau$) disconnected

The separation of the subset $[-1, 0) \cup (0,1)$ in $\mathbb{R}$ contains the limit point of the other

Example of a topological space that is connected, not locally connected and not path connected

$f$ has square root if and only if image of $f_*$ contained in $2 \mathbb Z$

Proof explanation to see that subset of $\mathbb{R}^2$ is not path connected.

equivalence of arakelian set definition

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