Question

Help with difficult telescoping series question: $\frac3{1!+2!+3!}+\frac4{2!+3!+4!}+\ldots+\frac{2012}{2010!+2011!+2012!}$

score 1.9k · Answer 1 · 2014-12-15 02:17:02

1.9k

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Help with difficult telescoping series question: $\frac3{1!+2!+3!}+\frac4{2!+3!+4!}+\ldots+\frac{2012}{2010!+2011!+2012!}$

Published on 15 Dec 2014 - 2:17

score 951 · Answer 2 · 2014-12-17 16:00:27

951

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Factorial inequality $2!\,4!\,6!\cdots (2n)!\geq\left((n+1)!\right)^n$ using induction

Published on 17 Dec 2014 - 16:00

score 364 · Answer 3 · 2014-12-18 00:24:55

364

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Writing number as sum of reciprocals of factorial

Published on 18 Dec 2014 - 0:24

score 19.3k · Answer 4 · 2026-03-28 15:26:56

19.3k

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How many digits are there in 100!?

Published on 28 Mar 2026 - 15:26

score 1.8k · Answer 5 · 2014-12-23 16:35:47

1.8k

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Other representations of factorial

Published on 23 Dec 2014 - 16:35

score 92 · Answer 6 · 2014-12-26 17:58:10

92

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Proving that $\sum_{i=0}^{n-p} \frac{i!}{(p+i)!} = \frac{1}{p-1}[\frac{1}{(p-1)!}-\frac{(n-p+1)!}{n!}]$

Published on 26 Dec 2014 - 17:58

score 3.2k · Answer 7 · 2014-12-28 03:00:47

3.2k

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general formula for permutations with some ordering

Published on 28 Dec 2014 - 3:00

score 17.4k · Answer 8 · 2014-12-29 07:29:58

17.4k

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For all $n>2$ there exists a prime number between $n$ and $ n!$

Published on 29 Dec 2014 - 7:29

score 408 · Answer 9 · 2014-12-31 08:44:22

408

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How many zeroes would be there at the end of $11^{(5!)!}-1$?

Published on 31 Dec 2014 - 8:44

score 9.3k · Answer 10 · 2015-01-01 15:47:59

9.3k

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Number of zeroes at end of factorial

Published on 01 Jan 2015 - 15:47

score 110 · Answer 11 · 2019-10-03 17:55:49

110

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Limit of $\frac{n!}{2^{(n^{2})}}$

Published on 03 Oct 2019 - 17:55

score 107 · Answer 12 · 2019-10-04 14:08:37

107

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Proving divisibility of a factorial

Published on 04 Oct 2019 - 14:08

score 73 · Answer 13 · 2019-10-05 18:40:07

73

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What is the maximum value of n such that the number $n!$ can be represented as a product of $(n−3)$ consecutive positive integers?

Published on 05 Oct 2019 - 18:40

score 43 · Answer 14 · 2019-10-06 03:14:55

43

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Why $1-\frac{1}{2!}+\frac{1}{3!}-...+(-1)^{n+1}\frac{1}{n!}\to 1-\frac{1}{e} $

Published on 06 Oct 2019 - 3:14

score 64 · Answer 15 · 2019-10-07 04:34:31

64

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Find number of matches in a tournament satisfying given conditions.

Published on 07 Oct 2019 - 4:34

List Question

Help with difficult telescoping series question: $\frac3{1!+2!+3!}+\frac4{2!+3!+4!}+\ldots+\frac{2012}{2010!+2011!+2012!}$

Factorial inequality $2!\,4!\,6!\cdots (2n)!\geq\left((n+1)!\right)^n$ using induction

Writing number as sum of reciprocals of factorial

How many digits are there in 100!?

Other representations of factorial

Proving that $\sum_{i=0}^{n-p} \frac{i!}{(p+i)!} = \frac{1}{p-1}[\frac{1}{(p-1)!}-\frac{(n-p+1)!}{n!}]$

general formula for permutations with some ordering

For all $n>2$ there exists a prime number between $n$ and $ n!$

How many zeroes would be there at the end of $11^{(5!)!}-1$?

Number of zeroes at end of factorial

Limit of $\frac{n!}{2^{(n^{2})}}$

Proving divisibility of a factorial

What is the maximum value of n such that the number $n!$ can be represented as a product of $(n−3)$ consecutive positive integers?

Why $1-\frac{1}{2!}+\frac{1}{3!}-...+(-1)^{n+1}\frac{1}{n!}\to 1-\frac{1}{e} $

Find number of matches in a tournament satisfying given conditions.

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