Question

Understanding the equivalence classes for $\Bbb R[x]/\langle x^2+1\rangle$

score 161 · Answer 1 · 2026-03-29 13:23:24

161

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Understanding the equivalence classes for $\Bbb R[x]/\langle x^2+1\rangle$

Published on 29 Mar 2026 - 13:23

score 350 · Answer 2 · 2026-03-28 12:02:35

350

Views

Why do the ideals have to be irreducible for finite fields?

Published on 28 Mar 2026 - 12:02

score 108 · Answer 3 · 2026-03-25 13:04:39

108

Views

Splitting field over field extenstion

Published on 25 Mar 2026 - 13:04

score 32 · Answer 4 · 2026-03-27 23:47:49

32

Views

How to find polynomial of minimal degeree?

Published on 27 Mar 2026 - 23:47

score 78 · Answer 5 · 2026-03-25 23:09:40

78

Views

Finding all $F $ automorphisms

Published on 25 Mar 2026 - 23:09

score 95 · Answer 6 · 2026-03-25 23:13:10

95

Views

If $\text{char}(k)=p$, $K=k(x,y), F=k(x^p,y^p)$, then $[K:F]=P^2$

Published on 25 Mar 2026 - 23:13

score 73 · Answer 7 · 2026-03-25 23:08:00

73

Views

Can we view a vector space as a field extention?

Published on 25 Mar 2026 - 23:08

score 26 · Answer 8 · 2018-05-23 10:16:15

26

Views

Finding all $\beta \in E$ such that $\beta^2 \in F$. Is it really this easy?

Published on 23 May 2018 - 10:16

score 76 · Answer 9 · 2026-03-28 01:25:56

76

Views

Galois extension $\mathbb{C}(X)/ \mathbb{C}(Y)$

Published on 28 Mar 2026 - 1:25

score 1k · Answer 10 · 2018-05-24 03:02:43

1k

Views

Why are all fields having order $p^{n}$ isomorphic to $(\Bbb Z_p)^{n}$ (under addition)?

Published on 24 May 2018 - 3:02

score 2.2k · Answer 11 · 2018-05-24 03:29:36

2.2k

Views

Clarification needed: Smallest subfield of a field

Published on 24 May 2018 - 3:29

score 65 · Answer 12 · 2026-03-28 01:25:54

65

Views

What degrees are possible for minimal polynomials?

Published on 28 Mar 2026 - 1:25

score 1k · Answer 13 · 2026-03-28 01:35:31

1k

Views

$\mathbb{Q}(\sqrt{6},\sqrt{10},\sqrt{15})=\mathbb{Q}(\alpha, \beta),$ for some $ \alpha $ and $\beta$?

Published on 28 Mar 2026 - 1:35

score 51 · Answer 14 · 2026-03-25 12:08:52

51

Views

Wedderburn's little theorem from a superalgebra point of view - reformulation from upper half-plane $H$ instead of $R^2$

Published on 25 Mar 2026 - 12:08

score 169 · Answer 15 · 2026-03-26 02:46:52

169

Views

$f=x^4+1$ is reducible over infinite field $F$ with characteristic $p>0$

Published on 26 Mar 2026 - 2:46

List Question

Understanding the equivalence classes for $\Bbb R[x]/\langle x^2+1\rangle$

Why do the ideals have to be irreducible for finite fields?

Splitting field over field extenstion

How to find polynomial of minimal degeree?

Finding all $F $ automorphisms

If $\text{char}(k)=p$, $K=k(x,y), F=k(x^p,y^p)$, then $[K:F]=P^2$

Can we view a vector space as a field extention?

Finding all $\beta \in E$ such that $\beta^2 \in F$. Is it really this easy?

Galois extension $\mathbb{C}(X)/ \mathbb{C}(Y)$

Why are all fields having order $p^{n}$ isomorphic to $(\Bbb Z_p)^{n}$ (under addition)?

Clarification needed: Smallest subfield of a field

What degrees are possible for minimal polynomials?

$\mathbb{Q}(\sqrt{6},\sqrt{10},\sqrt{15})=\mathbb{Q}(\alpha, \beta),$ for some $ \alpha $ and $\beta$?

Wedderburn's little theorem from a superalgebra point of view - reformulation from upper half-plane $H$ instead of $R^2$

$f=x^4+1$ is reducible over infinite field $F$ with characteristic $p>0$

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