Question

Reparametrization of the spherical harmonics so they will be complete in a different region.

score 61 · Answer 1 · 2026-05-10 19:43:14

61

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Reparametrization of the spherical harmonics so they will be complete in a different region.

Published on 10 May 2026 - 19:43

score 97 · Answer 2 · 2026-05-10 16:56:57

97

Views

Does it make sense to talk about "frequency" when expanding a function using spherical harmonics?

Published on 10 May 2026 - 16:56

score 3.4k · Answer 3 · 2026-05-11 09:48:02

3.4k

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The dot product of two vectors as the integral of two functions. Clarification please.

Published on 11 May 2026 - 9:48

score 72 · Answer 4 · 2026-05-10 12:30:58

72

Views

Neumann DBAR problem with tempered distributions

Published on 10 May 2026 - 12:30

score 38 · Answer 5 · 2026-05-10 15:46:43

38

Views

show that $f\in C^{l}(\mathbb{T})$. given $\sum_n |\hat f(n)||n|^{l} <\infty$

Published on 10 May 2026 - 15:46

score 61 · Answer 6 · 2026-04-13 17:35:00

61

Views

$L^{\infty}(\mathbb{T})$ and $C(\mathbb{T})$ do not admit conjugaison on circle?

Published on 13 Apr 2026 - 17:35

score 45 · Answer 7 · 2026-04-15 19:44:33

45

Views

If $f\in L^p(T)$, then there exists $g\in L^p(T)$ such that $\hat{f}(n)=\hat{g}(n)$ for every $n\geq 0$

Published on 15 Apr 2026 - 19:44

score 42 · Answer 8 · 2026-04-14 02:32:14

42

Views

Can I change limits of integration from $[-P/2,P/2]$ to $[0,P]$?

Published on 14 Apr 2026 - 2:32

score 102 · Answer 9 · 2026-04-16 15:05:00

102

Views

Does $\hbox{pv-}\!\!\int_{-1}^1\!\frac{f(x)}{x}dx:=\lim_{\epsilon\to0}\int_{\epsilon\le|x|\le1}\!\frac{f(x)}{x}dx$ exist for all $f\in C[-1,1]$?

Published on 16 Apr 2026 - 15:05

score 157 · Answer 10 · 2026-05-13 21:26:33

157

Views

The Integral of which the real part is the Poisson Integral of $f$, is Holomorphic

Published on 13 May 2026 - 21:26

score 339 · Answer 11 · 2026-05-05 11:15:36

339

Views

The measurability of convolution in locally compact group

Published on 05 May 2026 - 11:15

score 248 · Answer 12 · 2026-05-05 20:22:38

248

Views

"There are no smooth, symmetric, compactly supported wavelets."

Published on 05 May 2026 - 20:22

score 117 · Answer 13 · 2026-05-10 17:37:24

117

Views

Special case of Plancherel's implies Plancherel's

Published on 10 May 2026 - 17:37

score 108 · Answer 14 · 2026-05-12 23:56:35

108

Views

Can one take the Hilbert transform of an infinite-time "filtered" signal?

Published on 12 May 2026 - 23:56

score 83 · Answer 15 · 2026-04-16 01:41:24

83

Views

Relation between $\ell ^1$ and the $L^1$ space on the circle

Published on 16 Apr 2026 - 1:41

List Question

Reparametrization of the spherical harmonics so they will be complete in a different region.

Does it make sense to talk about "frequency" when expanding a function using spherical harmonics?

The dot product of two vectors as the integral of two functions. Clarification please.

Neumann DBAR problem with tempered distributions

show that $f\in C^{l}(\mathbb{T})$. given $\sum_n |\hat f(n)||n|^{l} <\infty$

$L^{\infty}(\mathbb{T})$ and $C(\mathbb{T})$ do not admit conjugaison on circle?

If $f\in L^p(T)$, then there exists $g\in L^p(T)$ such that $\hat{f}(n)=\hat{g}(n)$ for every $n\geq 0$

Can I change limits of integration from $[-P/2,P/2]$ to $[0,P]$?

Does $\hbox{pv-}\!\!\int_{-1}^1\!\frac{f(x)}{x}dx:=\lim_{\epsilon\to0}\int_{\epsilon\le|x|\le1}\!\frac{f(x)}{x}dx$ exist for all $f\in C[-1,1]$?

The Integral of which the real part is the Poisson Integral of $f$, is Holomorphic

The measurability of convolution in locally compact group

"There are no smooth, symmetric, compactly supported wavelets."

Special case of Plancherel's implies Plancherel's

Can one take the Hilbert transform of an infinite-time "filtered" signal?

Relation between $\ell ^1$ and the $L^1$ space on the circle

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