Question

Reparametrization of the spherical harmonics so they will be complete in a different region.

score 54 · Answer 1 · 2026-03-22 22:20:43

54

Views

Reparametrization of the spherical harmonics so they will be complete in a different region.

Published on 22 Mar 2026 - 22:20

score 88 · Answer 2 · 2026-03-22 20:07:22

88

Views

Does it make sense to talk about "frequency" when expanding a function using spherical harmonics?

Published on 22 Mar 2026 - 20:07

score 3.4k · Answer 3 · 2026-03-26 08:00:52

3.4k

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The dot product of two vectors as the integral of two functions. Clarification please.

Published on 26 Mar 2026 - 8:00

score 68 · Answer 4 · 2026-03-24 22:10:54

68

Views

Neumann DBAR problem with tempered distributions

Published on 24 Mar 2026 - 22:10

score 35 · Answer 5 · 2026-03-25 09:39:45

35

Views

show that $f\in C^{l}(\mathbb{T})$. given $\sum_n |\hat f(n)||n|^{l} <\infty$

Published on 25 Mar 2026 - 9:39

score 58 · Answer 6 · 2018-02-23 14:59:16

58

Views

$L^{\infty}(\mathbb{T})$ and $C(\mathbb{T})$ do not admit conjugaison on circle?

Published on 23 Feb 2018 - 14:59

score 42 · Answer 7 · 2018-02-23 17:10:00

42

Views

If $f\in L^p(T)$, then there exists $g\in L^p(T)$ such that $\hat{f}(n)=\hat{g}(n)$ for every $n\geq 0$

Published on 23 Feb 2018 - 17:10

score 39 · Answer 8 · 2018-02-23 17:44:58

39

Views

Can I change limits of integration from $[-P/2,P/2]$ to $[0,P]$?

Published on 23 Feb 2018 - 17:44

score 99 · Answer 9 · 2018-02-24 03:17:04

99

Views

Does $\hbox{pv-}\!\!\int_{-1}^1\!\frac{f(x)}{x}dx:=\lim_{\epsilon\to0}\int_{\epsilon\le|x|\le1}\!\frac{f(x)}{x}dx$ exist for all $f\in C[-1,1]$?

Published on 24 Feb 2018 - 3:17

score 154 · Answer 10 · 2026-03-29 07:28:58

154

Views

The Integral of which the real part is the Poisson Integral of $f$, is Holomorphic

Published on 29 Mar 2026 - 7:28

score 332 · Answer 11 · 2026-03-17 13:28:04

332

Views

The measurability of convolution in locally compact group

Published on 17 Mar 2026 - 13:28

score 239 · Answer 12 · 2026-03-17 12:37:05

239

Views

"There are no smooth, symmetric, compactly supported wavelets."

Published on 17 Mar 2026 - 12:37

score 114 · Answer 13 · 2026-03-25 04:40:23

114

Views

Special case of Plancherel's implies Plancherel's

Published on 25 Mar 2026 - 4:40

score 101 · Answer 14 · 2026-03-25 13:31:37

101

Views

Can one take the Hilbert transform of an infinite-time "filtered" signal?

Published on 25 Mar 2026 - 13:31

score 80 · Answer 15 · 2018-02-28 02:11:08

80

Views

Relation between $\ell ^1$ and the $L^1$ space on the circle

Published on 28 Feb 2018 - 2:11

List Question

Reparametrization of the spherical harmonics so they will be complete in a different region.

Does it make sense to talk about "frequency" when expanding a function using spherical harmonics?

The dot product of two vectors as the integral of two functions. Clarification please.

Neumann DBAR problem with tempered distributions

show that $f\in C^{l}(\mathbb{T})$. given $\sum_n |\hat f(n)||n|^{l} <\infty$

$L^{\infty}(\mathbb{T})$ and $C(\mathbb{T})$ do not admit conjugaison on circle?

If $f\in L^p(T)$, then there exists $g\in L^p(T)$ such that $\hat{f}(n)=\hat{g}(n)$ for every $n\geq 0$

Can I change limits of integration from $[-P/2,P/2]$ to $[0,P]$?

Does $\hbox{pv-}\!\!\int_{-1}^1\!\frac{f(x)}{x}dx:=\lim_{\epsilon\to0}\int_{\epsilon\le|x|\le1}\!\frac{f(x)}{x}dx$ exist for all $f\in C[-1,1]$?

The Integral of which the real part is the Poisson Integral of $f$, is Holomorphic

The measurability of convolution in locally compact group

"There are no smooth, symmetric, compactly supported wavelets."

Special case of Plancherel's implies Plancherel's

Can one take the Hilbert transform of an infinite-time "filtered" signal?

Relation between $\ell ^1$ and the $L^1$ space on the circle

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