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How to show that $\frac{1}{(1-\frac{1}{4}z^{-1})(1-\frac{1}{4}z)} = \frac{-4z^{-1}}{(1-\frac{1}{4}z^-1)(1-4z^{-1})}$

Published on 26 May 2013 - 12:09

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Show that $\frac{-4z^{-1}}{(1-\frac{1}{4}z^{-1})(1-4z^{-1})} = \frac{16}{15}\frac{1}{(1-\frac{1}{4}z^{-1})}-\frac{16}{15}\frac{1}{(1-4z^{-1})}$

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which parameters always make this rational equation evenly divisible?

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Proof for $\displaystyle\sum_{k=1}^n k^a$ equaling a sum of fractions

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question about partial fractions why $\frac{6x^2+19x+15}{(x-1)(x-2)^2}=\frac{A}{(x-1)}+\frac{B}{(x-2)}+\frac{C}{(x-2)^2}$

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Why is $\frac{1}{\frac{1}{X}}=X$?

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Published on 29 Jun 2013 - 5:54

List Question

Is it possible to rationalize a denominator containing two cube roots?

Solving Simple Mixed Fraction problem?

Tetration and its inverse to various exponents

How to show that $\frac{1}{(1-\frac{1}{4}z^{-1})(1-\frac{1}{4}z)} = \frac{-4z^{-1}}{(1-\frac{1}{4}z^-1)(1-4z^{-1})}$

Show that $\frac{-4z^{-1}}{(1-\frac{1}{4}z^{-1})(1-4z^{-1})} = \frac{16}{15}\frac{1}{(1-\frac{1}{4}z^{-1})}-\frac{16}{15}\frac{1}{(1-4z^{-1})}$

which parameters always make this rational equation evenly divisible?

Proof for $\displaystyle\sum_{k=1}^n k^a$ equaling a sum of fractions

question about partial fractions why $\frac{6x^2+19x+15}{(x-1)(x-2)^2}=\frac{A}{(x-1)}+\frac{B}{(x-2)}+\frac{C}{(x-2)^2}$

Why are only fractions with denominator 2 and 5 non-repeating?

removing the remainder of a fraction

Why is $\frac{1}{\frac{1}{X}}=X$?

Fractional overlap of 1/2 and 1/3

Reverse percentages

breaking up fractions

Ratio - Basic Question

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