Question

Does the origin have a strictly convex bounded neighborhood?

score 24 · Answer 1 · 2023-07-08 09:21:33

24

Views

Does the origin have a strictly convex bounded neighborhood?

Published on 08 Jul 2023 - 9:21

score 120 · Answer 2 · 2023-07-08 19:13:53

120

Views

Find subset of vectors which form basis

Published on 08 Jul 2023 - 19:13

score 87 · Answer 3 · 2023-09-28 21:26:44

87

Views

Finite Dimensional Subspace of a Normed Linear Space is complete.

Published on 28 Sep 2023 - 21:26

score 49 · Answer 4 · 2026-02-23 13:46:14

49

Views

If a basis for $V$ intersects an $m$-dimensional subspace of $V$ at $m$ basis vectors, will these $m$ vectors form a basis for the subspace?

Published on 23 Feb 2026 - 13:46

score 264 · Answer 5 · 2024-01-23 21:13:07

264

Views

Definition of an infinite dimensional vector space without the axiom of choice

Published on 23 Jan 2024 - 21:13

score 99 · Answer 6 · 2024-01-28 12:30:37

99

Views

Does "every normed vector space has a basis" imply choice

Published on 28 Jan 2024 - 12:30

score 139 · Answer 7 · 2024-02-20 14:01:17

139

Views

Basis for an infinite dimensional vector space

Published on 20 Feb 2024 - 14:01

score 16 · Answer 8 · 2024-03-09 21:30:03

16

Views

Brezis 5.28.2 About the competition of an orthogonal sequence

Published on 09 Mar 2024 - 21:30

score 80 · Answer 9 · 2024-03-19 01:16:24

80

Views

Confusion regarding orthonormal basis of $L^2[0, 1]$, in requiring $f(0) = f(1)$?

Published on 19 Mar 2024 - 1:16

score 35 · Answer 10 · 2024-03-22 20:16:25

35

Views

X is a vector space such that dim(X)=n. $M \subset X $ is a subspace. let $B=\{b_1,b_2,...,b_m\} $ is a hamel basis for M.

Published on 22 Mar 2024 - 20:16

score 587 · Answer 11 · 2015-02-08 13:34:27

587

Views

Can this proof of existence of a Hamel basis using transfinite recursion be shortened/simplified?

Published on 08 Feb 2015 - 13:34

score 1.8k · Answer 12 · 2026-03-24 06:57:35

1.8k

Views

Hamel Basis in Infinite dimensional Banach Space without Baire Category Theorem

Published on 24 Mar 2026 - 6:57

score 2.6k · Answer 13 · 2026-03-19 00:30:47

2.6k

Views

What is the basis of the vector space of real numbers over rational numbers?

Published on 19 Mar 2026 - 0:30

score 2.1k · Answer 14 · 2015-12-23 18:57:07

2.1k

Views

What's an example of a vector space that doesn't have a basis if we don't accept Choice?

Published on 23 Dec 2015 - 18:57

score 6.5k · Answer 15 · 2026-03-06 00:51:20

6.5k

Views

Proving that basis always exists and is not unique

Published on 06 Mar 2026 - 0:51

List Question

Does the origin have a strictly convex bounded neighborhood?

Find subset of vectors which form basis

Finite Dimensional Subspace of a Normed Linear Space is complete.

If a basis for $V$ intersects an $m$-dimensional subspace of $V$ at $m$ basis vectors, will these $m$ vectors form a basis for the subspace?

Definition of an infinite dimensional vector space without the axiom of choice

Does "every normed vector space has a basis" imply choice

Basis for an infinite dimensional vector space

Brezis 5.28.2 About the competition of an orthogonal sequence

Confusion regarding orthonormal basis of $L^2[0, 1]$, in requiring $f(0) = f(1)$?

X is a vector space such that dim(X)=n. $M \subset X $ is a subspace. let $B=\{b_1,b_2,...,b_m\} $ is a hamel basis for M.

Can this proof of existence of a Hamel basis using transfinite recursion be shortened/simplified?

Hamel Basis in Infinite dimensional Banach Space without Baire Category Theorem

What is the basis of the vector space of real numbers over rational numbers?

What's an example of a vector space that doesn't have a basis if we don't accept Choice?

Proving that basis always exists and is not unique

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