A finite dimensional vector space is a vector space which has a basis (linearly independent spanning subset) with finite cardinality.
If we accept the axiom of choice then it can be proven that every vector space has a (not necessarily finite) basis. The following are then equivalent:
- vector space V has no basis with finite cardinality
- vector space V has a basis with infinite cardinality
My question is, in a context where we haven't necessarily assumed the axiom of choice, is there a standard for selecting one of the two above (not necessarily equivalent) characterizations to be the definition of an infinite dimensional vector space?
My preference would be to call a vector space infinite dimensional if it admits a basis with infinite cardinality. This then leaves open the possibility for vector spaces which have no defined dimensionality since they admit no basis. But I don't know if this is standard.
A related question: The dimension theorem states that all bases for a vector space have the same cardinality. Can this theorem be proven without the axiom of choice? If not then the definition of an infinite dimensional vector space as being a vector space with infinite cardinality basis is not so good because, without the dimension theorem, one could imagine both a countable and uncountable basis for the same vector space. In this case I would prefer to say the dimensionality of the vector space is undefined.
Like many other things, this depends on what is the context in which you are working.
It is conceivable that you want to focus on vector spaces with a "well-defined dimension", namely, they have a basis, and all bases have the same cardinality.
Or that you want to limit yourself, at least, to vector spaces with bases (which you can at least reasonably bound in cardinality). As it is, indeed, consistent that there is a vector space with bases of different cardinality.
Or maybe you just want to refer to bases which are "not finitely dimensional", much like how an "infinite set" simply means "a set that is not finite".