Question

Integral of constant divided by polynomial and logarithm

score 146 · Answer 1 · 2014-12-02 03:53:09

146

Views

Integral of constant divided by polynomial and logarithm

Published on 02 Dec 2014 - 3:53

score 173 · Answer 2 · 2014-12-02 03:55:59

173

Views

Integral of constant divided by polynomial and another constant

Published on 02 Dec 2014 - 3:55

score 118 · Answer 3 · 2014-12-02 12:10:19

118

Views

Prove that $\int_{-1}^{1} 4x \sqrt{1-x^{2}}\, dx = -3\pi$

Published on 02 Dec 2014 - 12:10

score 574 · Answer 4 · 2014-12-02 18:05:24

574

Views

Convergence of integral of multiplication of two positive functions

Published on 02 Dec 2014 - 18:05

score 161 · Answer 5 · 2014-12-03 01:04:45

161

Views

How would I go about integrating an improper integral with an absolute value in the denominator?

Published on 03 Dec 2014 - 1:04

score 422 · Answer 6 · 2014-12-03 06:46:21

422

Views

Evaluating $ \int_{0}^{\infty}\frac{\ln (1+16x^2)}{1+25x^2}\mathrm d x$

Published on 03 Dec 2014 - 6:46

score 64 · Answer 7 · 2014-12-03 10:10:14

64

Views

Why does the improper integral $\int_{-1}^{1}\frac{e^x}{(x+1)}\mathrm d x$ diverge?

Published on 03 Dec 2014 - 10:10

score 345 · Answer 8 · 2014-12-04 08:14:35

345

Views

Evaluating $\int_0^1\frac{x^{-a}-x^{a}}{1-x}\,\mathrm dx$

Published on 04 Dec 2014 - 8:14

score 485 · Answer 9 · 2014-12-04 09:18:27

485

Views

Proving $\int_0^1\frac{\log 2-\log\left({1+\sqrt{1-x^2}}\right)}{x}dx=\frac{\left(\pi^2-12\log^22\right)}{24}$

Published on 04 Dec 2014 - 9:18

score 171 · Answer 10 · 2014-12-05 12:29:49

171

Views

Evaluating $\int_{-\infty}^{\infty} \frac{\cos x}{1+x^2} e^{-ixt} \,\mathrm dx$

Published on 05 Dec 2014 - 12:29

score 1.2k · Answer 11 · 2014-12-06 08:34:46

1.2k

Views

Is there other methods to evaluate $\int_1^{\infty}\frac{\{x\}-\frac{1}{2}}{x}\ \mathrm dx$?

Published on 06 Dec 2014 - 8:34

score 105 · Answer 12 · 2014-12-06 09:45:00

105

Views

Strange mistake when calculate improper integral

Published on 06 Dec 2014 - 9:45

score 210 · Answer 13 · 2014-12-06 19:55:50

210

Views

Find $\int _{-\infty}^{\infty}\frac{1}{x^{12} + 1} dx$ elementarily

Published on 06 Dec 2014 - 19:55

score 137 · Answer 14 · 2026-04-02 10:39:07

137

Views

improper integrals in q-calculus

Published on 02 Apr 2026 - 10:39

score 200 · Answer 15 · 2026-03-25 09:39:43

200

Views

In what sense is $\int_{-\infty }^{\infty } \frac{x}{x^2+1} \, dx = \pi i$?

Published on 25 Mar 2026 - 9:39

List Question

Integral of constant divided by polynomial and logarithm

Integral of constant divided by polynomial and another constant

Prove that $\int_{-1}^{1} 4x \sqrt{1-x^{2}}\, dx = -3\pi$

Convergence of integral of multiplication of two positive functions

How would I go about integrating an improper integral with an absolute value in the denominator?

Evaluating $ \int_{0}^{\infty}\frac{\ln (1+16x^2)}{1+25x^2}\mathrm d x$

Why does the improper integral $\int_{-1}^{1}\frac{e^x}{(x+1)}\mathrm d x$ diverge?

Evaluating $\int_0^1\frac{x^{-a}-x^{a}}{1-x}\,\mathrm dx$

Proving $\int_0^1\frac{\log 2-\log\left({1+\sqrt{1-x^2}}\right)}{x}dx=\frac{\left(\pi^2-12\log^22\right)}{24}$

Evaluating $\int_{-\infty}^{\infty} \frac{\cos x}{1+x^2} e^{-ixt} \,\mathrm dx$

Is there other methods to evaluate $\int_1^{\infty}\frac{\{x\}-\frac{1}{2}}{x}\ \mathrm dx$?

Strange mistake when calculate improper integral

Find $\int _{-\infty}^{\infty}\frac{1}{x^{12} + 1} dx$ elementarily

improper integrals in q-calculus

In what sense is $\int_{-\infty }^{\infty } \frac{x}{x^2+1} \, dx = \pi i$?

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