Question

Given a continous real function, it is almost globally Lipschitz:

score 123 · Answer 1 · 2021-12-08 18:09:26

123

Views

Given a continous real function, it is almost globally Lipschitz:

Published on 08 Dec 2021 - 18:09

score 215 · Answer 2 · 2021-12-09 16:35:55

215

Views

Bounding an $L$-smooth function $f$: $(x-y)^T \left[ \nabla f(x) - \nabla f(z) \right] \geq ? $

Published on 09 Dec 2021 - 16:35

score 50 · Answer 3 · 2026-03-31 13:31:27

50

Views

Proving single solution to an initial value problem

Published on 31 Mar 2026 - 13:31

score 128 · Answer 4 · 2021-12-19 09:05:00

128

Views

Example of a non-Lipschitz $f \in \mathrm{C}^1(U)$ where $U \subseteq \mathbb{R}^n$ is a non-convex compact connected set

Published on 19 Dec 2021 - 9:05

score 26 · Answer 5 · 2021-12-31 00:32:41

26

Views

Lipschitz continuity of $\sqrt{f}$ for $f(x) = \sup_{\alpha \in T} \sum_{i=1}^d \left(\sum_{j=1}^D \alpha_j x_{ij}\right)^2$

Published on 31 Dec 2021 - 0:32

score 327 · Answer 6 · 2026-03-30 03:34:49

327

Views

Relationship between smoothness and Lipschitzness

Published on 30 Mar 2026 - 3:34

score 85 · Answer 7 · 2022-01-05 08:10:09

85

Views

A nonnegative, integrable, Lipschitz function $f$ satisfies $\lim \inf_{n \rightarrow \infty} \sqrt{n}f(n) = 0$

Published on 05 Jan 2022 - 8:10

score 25 · Answer 8 · 2026-04-01 09:53:47

25

Views

Second Derivative of Lipchitz Concave Curve is infinite at only finite points

Published on 01 Apr 2026 - 9:53

score 86 · Answer 9 · 2022-01-10 02:04:28

86

Views

Lipschitz continuity of $f(x)=|x|$ on $[-1,1]$ with period $2.$

Published on 10 Jan 2022 - 2:04

score 187 · Answer 10 · 2022-01-11 01:25:32

187

Views

If $f$ is periodic and $C^1$ class, then Lipschitz continuous.

Published on 11 Jan 2022 - 1:25

score 146 · Answer 11 · 2026-03-29 22:36:27

146

Views

Does the following operation preserve Lipschitz continuity?

Published on 29 Mar 2026 - 22:36

score 578 · Answer 12 · 2022-01-13 04:08:20

578

Views

difference between lipschitz domain and domain satisfying the cone condition

Published on 13 Jan 2022 - 4:08

score 141 · Answer 13 · 2022-01-14 12:02:23

141

Views

When is a non-differentiable vector field a gradient field?

Published on 14 Jan 2022 - 12:02

score 404 · Answer 14 · 2022-01-15 18:35:16

404

Views

Do we have any way of knowing if natural phenomena in the real world follow the "Lipschitz Condition"?

Published on 15 Jan 2022 - 18:35

score 864 · Answer 15 · 2022-01-15 18:41:01

864

Views

Why is the Lipschitz Condition described using "Cones"?

Published on 15 Jan 2022 - 18:41

List Question

Given a continous real function, it is almost globally Lipschitz:

Bounding an $L$-smooth function $f$: $(x-y)^T \left[ \nabla f(x) - \nabla f(z) \right] \geq ? $

Proving single solution to an initial value problem

Example of a non-Lipschitz $f \in \mathrm{C}^1(U)$ where $U \subseteq \mathbb{R}^n$ is a non-convex compact connected set

Lipschitz continuity of $\sqrt{f}$ for $f(x) = \sup_{\alpha \in T} \sum_{i=1}^d \left(\sum_{j=1}^D \alpha_j x_{ij}\right)^2$

Relationship between smoothness and Lipschitzness

A nonnegative, integrable, Lipschitz function $f$ satisfies $\lim \inf_{n \rightarrow \infty} \sqrt{n}f(n) = 0$

Second Derivative of Lipchitz Concave Curve is infinite at only finite points

Lipschitz continuity of $f(x)=|x|$ on $[-1,1]$ with period $2.$

If $f$ is periodic and $C^1$ class, then Lipschitz continuous.

Does the following operation preserve Lipschitz continuity?

difference between lipschitz domain and domain satisfying the cone condition

When is a non-differentiable vector field a gradient field?

Do we have any way of knowing if natural phenomena in the real world follow the "Lipschitz Condition"?

Why is the Lipschitz Condition described using "Cones"?

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