Question

$B \subseteq A$ be an integral extension of integral domains where $B$ is normal; if $P \in Spec A$ and $Q=P\cap B$, then $\dim A_P=\dim B_Q$?

score 443 · Answer 1 · 2026-03-22 20:46:50

443

Views

$B \subseteq A$ be an integral extension of integral domains where $B$ is normal; if $P \in Spec A$ and $Q=P\cap B$, then $\dim A_P=\dim B_Q$?

Published on 22 Mar 2026 - 20:46

score 283 · Answer 2 · 2018-05-05 10:02:23

283

Views

Simple commutative algebra localisation problem that I just can't seem to see

Published on 05 May 2018 - 10:02

score 94 · Answer 3 · 2026-03-25 05:17:51

94

Views

ADMM Heuristic or rather stick to Branch and Bound?

Published on 25 Mar 2026 - 5:17

score 605 · Answer 4 · 2026-03-23 01:22:38

605

Views

Localization and flatness

Published on 23 Mar 2026 - 1:22

score 74 · Answer 5 · 2018-06-17 15:32:36

74

Views

Local homomorphisms on a fibered surface

Published on 17 Jun 2018 - 15:32

score 186 · Answer 6 · 2026-03-25 03:00:26

186

Views

Example for being an integral domain is not a local property.

Published on 25 Mar 2026 - 3:00

score 70 · Answer 7 · 2018-06-25 22:38:09

70

Views

Example of a ring $R$ and a prime $0\neq P\unlhd R$ such that $R_P$ is a field?

Published on 25 Jun 2018 - 22:38

score 440 · Answer 8 · 2018-06-28 02:09:01

440

Views

Subrings of localizations

Published on 28 Jun 2018 - 2:09

score 323 · Answer 9 · 2026-03-25 06:03:31

323

Views

Ring with finitely many maximal ideals whose localizations are Noetherian injects into $\bigoplus_{\mathfrak{m}}R_{\mathfrak{m}}$

Published on 25 Mar 2026 - 6:03

score 401 · Answer 10 · 2026-03-25 11:54:07

401

Views

Definition of “degree zero” in the localization of a graded ring

Published on 25 Mar 2026 - 11:54

score 348 · Answer 11 · 2026-03-25 03:01:07

348

Views

Can a non-PID noetherian integral domain have all PID localizations?

Published on 25 Mar 2026 - 3:01

score 56 · Answer 12 · 2026-03-25 09:49:28

56

Views

Discrete valuation arising from localizations of $R[[t]]$

Published on 25 Mar 2026 - 9:49

score 78 · Answer 13 · 2018-07-31 16:57:05

78

Views

Show that $S^{-1}A = B$ for integral domains and $S = \{x\in A\setminus\{0\}: x^{-1}\in B\}$

Published on 31 Jul 2018 - 16:57

score 418 · Answer 14 · 2026-03-25 03:22:55

418

Views

Inclusion of Reflective Subcategory Creates Limits

Published on 25 Mar 2026 - 3:22

score 76 · Answer 15 · 2018-08-13 05:39:18

76

Views

Show that $z - xy$ is in the ideal $I = \langle 2x-1, 3y-1, 6z-1 \rangle$ in $\mathbb{Z}[x,y,z]$

Published on 13 Aug 2018 - 5:39

List Question

$B \subseteq A$ be an integral extension of integral domains where $B$ is normal; if $P \in Spec A$ and $Q=P\cap B$, then $\dim A_P=\dim B_Q$?

Simple commutative algebra localisation problem that I just can't seem to see

ADMM Heuristic or rather stick to Branch and Bound?

Localization and flatness

Local homomorphisms on a fibered surface

Example for being an integral domain is not a local property.

Example of a ring $R$ and a prime $0\neq P\unlhd R$ such that $R_P$ is a field?

Subrings of localizations

Ring with finitely many maximal ideals whose localizations are Noetherian injects into $\bigoplus_{\mathfrak{m}}R_{\mathfrak{m}}$

Definition of “degree zero” in the localization of a graded ring

Can a non-PID noetherian integral domain have all PID localizations?

Discrete valuation arising from localizations of $R[[t]]$

Show that $S^{-1}A = B$ for integral domains and $S = \{x\in A\setminus\{0\}: x^{-1}\in B\}$

Inclusion of Reflective Subcategory Creates Limits

Show that $z - xy$ is in the ideal $I = \langle 2x-1, 3y-1, 6z-1 \rangle$ in $\mathbb{Z}[x,y,z]$

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