Let $R$ be a DVR and consider the ring of power series $R[[t]]$. Now let $\mathfrak p\subset R[[t]]$ be a prime ideal of height $1$.
Why the localization $R[[t]]_{\mathfrak p}$ is again a DVR?
Let $R$ be a DVR and consider the ring of power series $R[[t]]$. Now let $\mathfrak p\subset R[[t]]$ be a prime ideal of height $1$.
Why the localization $R[[t]]_{\mathfrak p}$ is again a DVR?
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The ring $R[[t]]$ is local of dimension $2$. Furthermore, its maximal ideal is generated by two elements, a uniformizing parameter of $R$ and $t$. Thus, $R[[t]]$ is regular. A localization of a regular ring is regular, and a regular local ring of dimension 1 is a DVR.