List questions from lp-spaces

Published on 04 Apr 2026 - 0:16

105

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Compactness of a linear function

Published on 27 Mar 2026 - 14:55

77

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Convergence in $L^1(0,1)$

Published on 12 Sep 2016 - 18:56

525

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Series of $L^2$ functions converges pointwise almost everywhere

Published on 13 Sep 2016 - 15:22

145

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How "subsets" and "embedding" differs?

Published on 15 Sep 2016 - 13:13

74

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$\ell_{p}$ spaces: Differences between $p$ and $p'$

Published on 16 Sep 2016 - 3:01

101

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Show that $H$ is a Banach space

Published on 04 Apr 2026 - 17:55

118

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$f\in L^{2} \implies \int_{n}^{n+1} f(x) dx \to 0$?

Published on 20 Sep 2016 - 4:21

22

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If $\|u\|_{2}<\infty $ then $\|u\|_{p}<\infty (p>2)$?

Published on 04 Apr 2026 - 17:54

121

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Inclusion Of Unit Open Ball

Published on 20 Sep 2016 - 19:34

815

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Showing that $\ell_1\subset\ell_2\subset c_0\subset\ell_\infty$

Published on 20 Sep 2016 - 23:25

93

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$L^p_0(\Omega)\cap L^p(\Omega)$ dense in $L^p(\Omega)$ when $m(\Omega)=\infty$?

Published on 21 Sep 2016 - 5:06

24

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How translation plays a role to create a pointwise convergence in $\ell^{1}(\mathbb Z)$?

Published on 21 Sep 2016 - 11:32

45

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If $0\leq \alpha\leq1$, then $f(x)=x^{-\alpha}$ is not $L^{1}$ on $[1,\infty)$. But $f(x)$ is $L^{\infty}$ on $[1,\infty)$. How to show this

Published on 23 Sep 2016 - 11:47

328

Views

norms of $L^q(\Omega)$ and $L^r(\Omega)$ are not equivalent

Published on 23 Sep 2016 - 18:10

List Question

If $u\in H_{0}^{m}(\Omega)$ then $\|D^{m} f(u)\|_{2}<+\infty $?

Compactness of a linear function

Convergence in $L^1(0,1)$

Series of $L^2$ functions converges pointwise almost everywhere

How "subsets" and "embedding" differs?

$\ell_{p}$ spaces: Differences between $p$ and $p'$

Show that $H$ is a Banach space

$f\in L^{2} \implies \int_{n}^{n+1} f(x) dx \to 0$?

If $\|u\|_{2}<\infty $ then $\|u\|_{p}<\infty (p>2)$?

Inclusion Of Unit Open Ball

Showing that $\ell_1\subset\ell_2\subset c_0\subset\ell_\infty$

$L^p_0(\Omega)\cap L^p(\Omega)$ dense in $L^p(\Omega)$ when $m(\Omega)=\infty$?

How translation plays a role to create a pointwise convergence in $\ell^{1}(\mathbb Z)$?

If $0\leq \alpha\leq1$, then $f(x)=x^{-\alpha}$ is not $L^{1}$ on $[1,\infty)$. But $f(x)$ is $L^{\infty}$ on $[1,\infty)$. How to show this

norms of $L^q(\Omega)$ and $L^r(\Omega)$ are not equivalent

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