Question

Prove using natural deduction $((P \land Q) \rightarrow R) \vdash (P \rightarrow R) \lor (Q\rightarrow R)$

score 640 · Answer 1 · 2016-02-08 06:14:56

640

Views

Prove using natural deduction $((P \land Q) \rightarrow R) \vdash (P \rightarrow R) \lor (Q\rightarrow R)$

Published on 08 Feb 2016 - 6:14

score 165 · Answer 2 · 2016-02-08 06:56:32

165

Views

Prove using natural deduction that $(R \rightarrow (P \rightarrow Q))\vdash (Q\rightarrow P) \lor (P \rightarrow Q)$

Published on 08 Feb 2016 - 6:56

score 115 · Answer 3 · 2016-02-08 21:54:15

115

Views

Proof using formal deduction, how to introduce a conclusion?

Published on 08 Feb 2016 - 21:54

score 127 · Answer 4 · 2026-03-25 07:46:35

127

Views

Deductive logic counter-intuitive result

Published on 25 Mar 2026 - 7:46

score 1.4k · Answer 5 · 2016-02-11 06:18:23

1.4k

Views

Inference Rules, Not(P) Implies Not(Q) / Q Implies P

Published on 11 Feb 2016 - 6:18

score 2.2k · Answer 6 · 2016-02-11 23:25:42

2.2k

Views

Natural deduction proof / Formal proof : Complicated conclusion with no premise

Published on 11 Feb 2016 - 23:25

score 140 · Answer 7 · 2016-02-21 13:13:25

140

Views

Formally prove the following equations using propositional logic

Published on 21 Feb 2016 - 13:13

score 343 · Answer 8 · 2016-02-21 17:08:17

343

Views

Calculational proofs and Natural Deduction system.

Published on 21 Feb 2016 - 17:08

score 335 · Answer 9 · 2016-02-29 19:58:06

335

Views

How does one prove the following using natural deduction: $a ∧ ¬a \vdash b ∧ ¬b$

Published on 29 Feb 2016 - 19:58

score 334 · Answer 10 · 2016-03-08 03:44:44

334

Views

Why not include another assumption within this natural deduction proof?

Published on 08 Mar 2016 - 3:44

score 279 · Answer 11 · 2016-03-10 11:49:38

279

Views

Natural deduction proof without assumption

Published on 10 Mar 2016 - 11:49

score 5.4k · Answer 12 · 2026-03-22 16:29:56

5.4k

Views

Modus Tollens Proof

Published on 22 Mar 2026 - 16:29

score 104 · Answer 13 · 2026-02-23 13:43:10

104

Views

How do I derive a proper natural deduction proof for $\{(\phi\leftrightarrow(\psi\leftrightarrow\psi))\}\vdash\phi$?

Published on 23 Feb 2026 - 13:43

score 227 · Answer 14 · 2026-02-23 13:46:14

227

Views

The textbook's way of deriving a natural deduction proof of $\vdash((\phi\leftrightarrow\psi)\leftrightarrow\phi)$ feels wrong.

Published on 23 Feb 2026 - 13:46

score 269 · Answer 15 · 2026-02-23 13:46:23

269

Views

The textbook's natural deduction proof for $\vdash(\neg(\phi\to\psi)\to\phi)$ seems to be wrong with regard to RAA(Reductio Ad Absurdum).

Published on 23 Feb 2026 - 13:46

List Question

Prove using natural deduction $((P \land Q) \rightarrow R) \vdash (P \rightarrow R) \lor (Q\rightarrow R)$

Prove using natural deduction that $(R \rightarrow (P \rightarrow Q))\vdash (Q\rightarrow P) \lor (P \rightarrow Q)$

Proof using formal deduction, how to introduce a conclusion?

Deductive logic counter-intuitive result

Inference Rules, Not(P) Implies Not(Q) / Q Implies P

Natural deduction proof / Formal proof : Complicated conclusion with no premise

Formally prove the following equations using propositional logic

Calculational proofs and Natural Deduction system.

How does one prove the following using natural deduction: $a ∧ ¬a \vdash b ∧ ¬b$

Why not include another assumption within this natural deduction proof?

Natural deduction proof without assumption

Modus Tollens Proof

How do I derive a proper natural deduction proof for $\{(\phi\leftrightarrow(\psi\leftrightarrow\psi))\}\vdash\phi$?

The textbook's way of deriving a natural deduction proof of $\vdash((\phi\leftrightarrow\psi)\leftrightarrow\phi)$ feels wrong.

The textbook's natural deduction proof for $\vdash(\neg(\phi\to\psi)\to\phi)$ seems to be wrong with regard to RAA(Reductio Ad Absurdum).

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