Question

Noetherian domain and localization

score 92 · Answer 1 · 2026-03-22 01:51:34

92

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Noetherian domain and localization

Published on 22 Mar 2026 - 1:51

score 69 · Answer 2 · 2026-03-24 23:44:27

69

Views

More aesthetically pleasing proof of lifting.

Published on 24 Mar 2026 - 23:44

score 108 · Answer 3 · 2018-04-20 18:29:27

108

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If $B$ is a Noetherian ring and $A$ is a subring of $B$, is $B$ Noetherian as an $A$ module?

Published on 20 Apr 2018 - 18:29

score 279 · Answer 4 · 2026-03-17 08:47:48

279

Views

$R$ be Noetherian ring. Let $I \subseteq J$ be proper ideals of $R$. If $R$ is $J$-adically complete, then is $R$ complete $I$-adically?

Published on 17 Mar 2026 - 8:47

score 272 · Answer 5 · 2026-03-17 13:50:06

272

Views

$I$ be a finitely generated ideal of $R$ such that $R/I$ is a Noetherian and $R$ is $I$-adically complete. Then $R$ is Noetherian

Published on 17 Mar 2026 - 13:50

score 80 · Answer 6 · 2026-03-17 14:31:30

80

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$R$ is Noetherian semilocal. $J:=\operatorname{Jac}(R)$. If $R/\operatorname{nil}(R)$ is $J$-adically complete, then $R$ is $J$-adically complete

Published on 17 Mar 2026 - 14:31

score 405 · Answer 7 · 2018-04-25 20:57:19

405

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Any module over a regular local ring has finite free resolution

Published on 25 Apr 2018 - 20:57

score 385 · Answer 8 · 2026-03-22 16:53:15

385

Views

Question about Hopkins-Levitzki Theorem's proof

Published on 22 Mar 2026 - 16:53

score 434 · Answer 9 · 2018-04-29 03:30:49

434

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Tensor product of noetherian modules is also noetherian?

Published on 29 Apr 2018 - 3:30

score 1.6k · Answer 10 · 2018-05-03 19:57:03

1.6k

Views

Example of non-Noetherian ring

Published on 03 May 2018 - 19:57

score 103 · Answer 11 · 2018-05-06 18:06:54

103

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Descending chain condition of maximal ideals for a domain

Published on 06 May 2018 - 18:06

score 149 · Answer 12 · 2018-05-07 21:11:34

149

Views

Proving a ring $A$, generated by Noetherian subring and nilpotent element, is Noetherian again.

Published on 07 May 2018 - 21:11

score 395 · Answer 13 · 2026-03-22 22:16:29

395

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Jacobson local ring that is not Artinian

Published on 22 Mar 2026 - 22:16

score 208 · Answer 14 · 2018-05-27 14:24:07

208

Views

Ring Homomorphisms and Noetherian...?

Published on 27 May 2018 - 14:24

score 202 · Answer 15 · 2018-06-03 06:19:56

202

Views

Commutative, infinite, Noetherian ring with no non-trivial nilpotent and no non-trivial idempotent

Published on 03 Jun 2018 - 6:19

List Question

Noetherian domain and localization

More aesthetically pleasing proof of lifting.

If $B$ is a Noetherian ring and $A$ is a subring of $B$, is $B$ Noetherian as an $A$ module?

$R$ be Noetherian ring. Let $I \subseteq J$ be proper ideals of $R$. If $R$ is $J$-adically complete, then is $R$ complete $I$-adically?

$I$ be a finitely generated ideal of $R$ such that $R/I$ is a Noetherian and $R$ is $I$-adically complete. Then $R$ is Noetherian

$R$ is Noetherian semilocal. $J:=\operatorname{Jac}(R)$. If $R/\operatorname{nil}(R)$ is $J$-adically complete, then $R$ is $J$-adically complete

Any module over a regular local ring has finite free resolution

Question about Hopkins-Levitzki Theorem's proof

Tensor product of noetherian modules is also noetherian?

Example of non-Noetherian ring

Descending chain condition of maximal ideals for a domain

Proving a ring $A$, generated by Noetherian subring and nilpotent element, is Noetherian again.

Jacobson local ring that is not Artinian

Ring Homomorphisms and Noetherian...?

Commutative, infinite, Noetherian ring with no non-trivial nilpotent and no non-trivial idempotent

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