Question

a condition equivalent to compactness in linearly ordered spaces

score 196 · Answer 1 · 2026-02-23 13:47:40

196

Views

a condition equivalent to compactness in linearly ordered spaces

Published on 23 Feb 2026 - 13:47

score 248 · Answer 2 · 2026-02-23 13:40:38

248

Views

Ordered set in order topology

Published on 23 Feb 2026 - 13:40

score 675 · Answer 3 · 2026-02-23 13:41:36

675

Views

Order Topology on $\mathbb{Z_+}$

Published on 23 Feb 2026 - 13:41

score 713 · Answer 4 · 2026-02-23 13:46:24

713

Views

Prove that if $\{K_n\}_{n\in\mathbb{N}}$ is a sequence of uncountable compact sets of $X$, then $\bigcap\limits_{n\in\mathbb{N}}K_n$ is uncountable

Published on 23 Feb 2026 - 13:46

score 1.6k · Answer 5 · 2026-02-23 13:45:00

1.6k

Views

Topology - closures of intervals with the order topology

Published on 23 Feb 2026 - 13:45

score 197 · Answer 6 · 2026-02-23 13:40:31

197

Views

Linearly ordered X is regular

Published on 23 Feb 2026 - 13:40

score 413 · Answer 7 · 2026-02-23 13:42:57

413

Views

A totally ordered ring with its order topology is not a topological ring.

Published on 23 Feb 2026 - 13:42

score 668 · Answer 8 · 2026-02-23 13:47:43

668

Views

Existence of continuous order-preserving function

Published on 23 Feb 2026 - 13:47

score 325 · Answer 9 · 2026-02-23 13:46:13

325

Views

Show the $\omega_1$-line (long line) is not homeomorphic and not order isomorphic to $[0,1)$

Published on 23 Feb 2026 - 13:46

score 230 · Answer 10 · 2026-02-23 13:47:41

230

Views

linear ordered topological spaces are $T_4$- guided proof.

Published on 23 Feb 2026 - 13:47

score 1k · Answer 11 · 2026-02-23 13:46:56

1k

Views

$X$ and $Y$ are ordered set, $f:X\rightarrow Y$ is order preserving and surjective, then $f$ is a homeomorphism.

Published on 23 Feb 2026 - 13:46

score 602 · Answer 12 · 2026-02-23 13:45:00

602

Views

The closure of $(a;b)$ in an order topology

Published on 23 Feb 2026 - 13:45

score 704 · Answer 13 · 2026-02-23 13:44:59

704

Views

Show that R^2 with the dictionary order topology is homeomorphic to Rd * R.

Published on 23 Feb 2026 - 13:44

score 702 · Answer 14 · 2026-02-23 13:44:39

702

Views

questions about subspace topology, order topology and convex subset

Published on 23 Feb 2026 - 13:44

score 89 · Answer 15 · 2026-02-23 13:44:59

89

Views

Is the interval $((a,b), (a,d))$ is open in $\mathbb{R}\times \mathbb{R}$ which is equipped with the dictionary order topology

Published on 23 Feb 2026 - 13:44

List Question

a condition equivalent to compactness in linearly ordered spaces

Ordered set in order topology

Order Topology on $\mathbb{Z_+}$

Prove that if $\{K_n\}_{n\in\mathbb{N}}$ is a sequence of uncountable compact sets of $X$, then $\bigcap\limits_{n\in\mathbb{N}}K_n$ is uncountable

Topology - closures of intervals with the order topology

Linearly ordered X is regular

A totally ordered ring with its order topology is not a topological ring.

Existence of continuous order-preserving function

Show the $\omega_1$-line (long line) is not homeomorphic and not order isomorphic to $[0,1)$

linear ordered topological spaces are $T_4$- guided proof.

$X$ and $Y$ are ordered set, $f:X\rightarrow Y$ is order preserving and surjective, then $f$ is a homeomorphism.

The closure of $(a;b)$ in an order topology

Show that R^2 with the dictionary order topology is homeomorphic to Rd * R.

questions about subspace topology, order topology and convex subset

Is the interval $((a,b), (a,d))$ is open in $\mathbb{R}\times \mathbb{R}$ which is equipped with the dictionary order topology

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