Question

In the diagram, given that $ADGB$ is an isosceles trapezoid, $CE = CD, BC = BD,$ $\angle AOD = 30^{\circ} $, prove that $BD = DF$.

score 130 · Answer 1 · 2026-04-02 04:51:12

130

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In the diagram, given that $ADGB$ is an isosceles trapezoid, $CE = CD, BC = BD,$ $\angle AOD = 30^{\circ} $, prove that $BD = DF$.

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List Question

In the diagram, given that $ADGB$ is an isosceles trapezoid, $CE = CD, BC = BD,$ $\angle AOD = 30^{\circ} $, prove that $BD = DF$.

Proving that the plane is nonempty

Help me understand this topological proof

Plane equations

How do I align these letters to the same baseline?

How to shrink a 3d plane in local direction

Inscribed circle in general case

Proving what the isometry group of a "chess board" is

Linear algebra line and plane positions

Possible corollary of Jordan's curve theorem

Use of edge words and connected sums in the classification of surfaces

How to find the normal vector to a plane with complex coefficients?

Maximum number of squares a line of length n will intersect

Predict Collision Between 2 Uniform Circular Motion Objects

$O$ is the circumcenter of non-right $\triangle ABC$. $\frac{|AB \cdot CO|}{|AC \cdot BO|} = \frac{|AB \cdot BO|}{|AC \cdot CO|} = 3$. Find $\tan A$

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