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15
Math.TechQA.Club
2026-04-16 03:23:32
709
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Points on $(x^2 + y^2)^2 = 2x^2 - 2y^2$ with slope of $1$
Published on
16 Apr 2026 - 3:23
#calculus
#derivatives
#graphing-functions
#polar-coordinates
84
Views
Polar Coordinates
Published on
14 Apr 2026 - 14:22
#integration
#definite-integrals
#polar-coordinates
22.5k
Views
Converting Cartesian circle to polar form
Published on
13 Apr 2026 - 0:04
#polar-coordinates
44
Views
Polar coordinates: Slope of tangent
Published on
14 Apr 2026 - 21:03
#derivatives
#self-learning
#polar-coordinates
121
Views
Representation of cardiod in the complex plane
Published on
11 Apr 2026 - 18:09
#geometry
#trigonometry
#complex-numbers
#polar-coordinates
1k
Views
Plotting complicated polar curve without calculator
Published on
16 Apr 2026 - 14:15
#polar-coordinates
1.5k
Views
Arc Length polar curve
Published on
13 Apr 2026 - 20:59
#calculus
#polar-coordinates
1.1k
Views
Convert the polar equation to Cartesian coordinates : $r^3 = − 7cos\theta$
Published on
09 Apr 2026 - 6:39
#polar-coordinates
1.9k
Views
Cylindrical coordinates: $\iiint (x^2 + y^2 + z^2) dxdydz$
Published on
15 Apr 2026 - 16:47
#integration
#definite-integrals
#polar-coordinates
1.2k
Views
Volume of solid bounded by $z^2 = x^2 + y^2$ and $x^2 + y^2 = 2x$
Published on
17 Apr 2026 - 12:40
#multivariable-calculus
#definite-integrals
#polar-coordinates
#volume
50
Views
polar co ordinates integration
Published on
17 Apr 2026 - 10:12
#integration
#definite-integrals
#indefinite-integrals
#polar-coordinates
#dirac-delta
180
Views
If $f(2\alpha-\theta) = f(\theta)$, then $\theta=\alpha$ is a line of symmetry of $r=f(\theta)$. How do you derive $f(2\alpha-\theta) = f(\theta)$?
Published on
16 Apr 2026 - 8:23
#intuition
#polar-coordinates
1.8k
Views
Integral formula for polar coordinates
Published on
11 Apr 2026 - 20:25
#real-analysis
#polar-coordinates
128
Views
Find k in $\int_2^{\infty} \frac{k}{\sqrt{2\pi}} \exp^{-\frac{1}{2} x^2} \, dx$
Published on
17 Apr 2026 - 14:44
#calculus
#integration
#polar-coordinates
1.2k
Views
how to find slope of this polar curve: $r^2=\sin(2\theta)$.
Published on
14 Apr 2026 - 2:01
#calculus
#derivatives
#polar-coordinates
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