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15
Math.TechQA.Club
2014-05-08 03:30:32
706
Views
Points on $(x^2 + y^2)^2 = 2x^2 - 2y^2$ with slope of $1$
Published on
08 May 2014 - 3:30
#calculus
#derivatives
#graphing-functions
#polar-coordinates
81
Views
Polar Coordinates
Published on
08 May 2014 - 20:01
#integration
#definite-integrals
#polar-coordinates
22.5k
Views
Converting Cartesian circle to polar form
Published on
11 May 2014 - 10:41
#polar-coordinates
41
Views
Polar coordinates: Slope of tangent
Published on
11 May 2014 - 11:40
#derivatives
#self-learning
#polar-coordinates
118
Views
Representation of cardiod in the complex plane
Published on
16 May 2014 - 20:21
#geometry
#trigonometry
#complex-numbers
#polar-coordinates
1k
Views
Plotting complicated polar curve without calculator
Published on
17 May 2014 - 23:51
#polar-coordinates
1.5k
Views
Arc Length polar curve
Published on
18 May 2014 - 0:29
#calculus
#polar-coordinates
1.1k
Views
Convert the polar equation to Cartesian coordinates : $r^3 = − 7cos\theta$
Published on
18 May 2014 - 8:09
#polar-coordinates
1.9k
Views
Cylindrical coordinates: $\iiint (x^2 + y^2 + z^2) dxdydz$
Published on
19 May 2014 - 14:15
#integration
#definite-integrals
#polar-coordinates
1.2k
Views
Volume of solid bounded by $z^2 = x^2 + y^2$ and $x^2 + y^2 = 2x$
Published on
28 Mar 2026 - 7:45
#multivariable-calculus
#definite-integrals
#polar-coordinates
#volume
46
Views
polar co ordinates integration
Published on
27 Mar 2026 - 2:39
#integration
#definite-integrals
#indefinite-integrals
#polar-coordinates
#dirac-delta
177
Views
If $f(2\alpha-\theta) = f(\theta)$, then $\theta=\alpha$ is a line of symmetry of $r=f(\theta)$. How do you derive $f(2\alpha-\theta) = f(\theta)$?
Published on
20 May 2014 - 2:48
#intuition
#polar-coordinates
1.7k
Views
Integral formula for polar coordinates
Published on
23 May 2014 - 12:00
#real-analysis
#polar-coordinates
125
Views
Find k in $\int_2^{\infty} \frac{k}{\sqrt{2\pi}} \exp^{-\frac{1}{2} x^2} \, dx$
Published on
26 May 2014 - 13:35
#calculus
#integration
#polar-coordinates
1.2k
Views
how to find slope of this polar curve: $r^2=\sin(2\theta)$.
Published on
27 May 2014 - 16:15
#calculus
#derivatives
#polar-coordinates
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