Question

Proof that $x=a$ is solution of polynomial $P(x)=(x-a)Q(x)$

score 221 · Answer 1 · 2026-03-28 04:34:51

221

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Proof that $x=a$ is solution of polynomial $P(x)=(x-a)Q(x)$

Published on 28 Mar 2026 - 4:34

score 537 · Answer 2 · 2026-03-22 16:37:32

537

Views

Why is the set of all $x \in \mathbb{R}$ satisfying $ x^2 - 8x + 15 \leq 0 $ representable as a polyhedron?

Published on 22 Mar 2026 - 16:37

score 40 · Answer 3 · 2018-03-03 15:21:57

40

Views

Number of values of a for common roots

Published on 03 Mar 2018 - 15:21

score 34 · Answer 4 · 2026-03-28 10:40:37

34

Views

Area where a polynomial in several variables is non-negative

Published on 28 Mar 2026 - 10:40

score 430 · Answer 5 · 2018-03-03 16:04:22

430

Views

Proof reference: Power series expansion of an inverse polynomial

Published on 03 Mar 2018 - 16:04

score 50 · Answer 6 · 2026-03-25 18:49:48

50

Views

Does the same construction that yields $K$-vector spaces when $K$ is a field yield free $K$-modules when $K$ is a ring?

Published on 25 Mar 2026 - 18:49

score 66 · Answer 7 · 2026-03-25 19:25:11

66

Views

How we do solve this problem

Published on 25 Mar 2026 - 19:25

score 146 · Answer 8 · 2026-03-22 20:36:50

146

Views

Isomorphism of rings between 2 non fields

Published on 22 Mar 2026 - 20:36

score 34 · Answer 9 · 2018-03-03 19:31:25

34

Views

Equation and polynomial

Published on 03 Mar 2018 - 19:31

score 453 · Answer 10 · 2026-03-25 15:17:56

453

Views

Exercise 1.4.12 of Ideals, Varieties, and Algorithms

Published on 25 Mar 2026 - 15:17

score 75 · Answer 11 · 2026-03-26 04:21:39

75

Views

Relationship between coefficients and polynomial roots using induction proof?

Published on 26 Mar 2026 - 4:21

score 329 · Answer 12 · 2018-03-04 00:38:20

329

Views

If $P$ is a polynomial with $|P(1)| = \max\limits_{|z| =1} |P(z)|$, then its root on the unit circle is separated away from 0

Published on 04 Mar 2018 - 0:38

score 127 · Answer 13 · 2018-03-04 00:42:22

127

Views

Finding a new polynomial with roots $k$ greater than a given polynomial

Published on 04 Mar 2018 - 0:42

score 161 · Answer 14 · 2026-03-25 01:18:58

161

Views

Factorize $\det\left[\begin{smallmatrix}yz-x^2&zx-y^2&xy-z^2\\zx-y^2&xy-z^2&yz-x^2\\xy-z^2&yz-x^2&zx-y^2\end{smallmatrix}\right]$ using factor theorem

Published on 25 Mar 2026 - 1:18

score 147 · Answer 15 · 2026-03-27 10:43:00

147

Views

$p(\lambda) = 0$ when $\deg p$ is minimal implies that $\lambda$ is an eigenvalue

Published on 27 Mar 2026 - 10:43

List Question

Proof that $x=a$ is solution of polynomial $P(x)=(x-a)Q(x)$

Why is the set of all $x \in \mathbb{R}$ satisfying $ x^2 - 8x + 15 \leq 0 $ representable as a polyhedron?

Number of values of a for common roots

Area where a polynomial in several variables is non-negative

Proof reference: Power series expansion of an inverse polynomial

Does the same construction that yields $K$-vector spaces when $K$ is a field yield free $K$-modules when $K$ is a ring?

How we do solve this problem

Isomorphism of rings between 2 non fields

Equation and polynomial

Exercise 1.4.12 of Ideals, Varieties, and Algorithms

Relationship between coefficients and polynomial roots using induction proof?

If $P$ is a polynomial with $|P(1)| = \max\limits_{|z| =1} |P(z)|$, then its root on the unit circle is separated away from 0

Finding a new polynomial with roots $k$ greater than a given polynomial

Factorize $\det\left[\begin{smallmatrix}yz-x^2&zx-y^2&xy-z^2\\zx-y^2&xy-z^2&yz-x^2\\xy-z^2&yz-x^2&zx-y^2\end{smallmatrix}\right]$ using factor theorem

$p(\lambda) = 0$ when $\deg p$ is minimal implies that $\lambda$ is an eigenvalue

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