$\forall x(P(x) \rightarrow Q(x))\stackrel{?}{\equiv}\neg\exists x(P(x) \rightarrow \neg Q(x))\stackrel{?}{\equiv}\neg\exists x(P(x) \wedge\neg Q(x))$

score 206 · Answer 13 · 2026-03-28 10:04:38

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The quantifiers in the definition of almost sure convergence

Published on 28 Mar 2026 - 10:04

score 62 · Answer 14 · 2024-02-01 17:02:29

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Quantifiers and the meaning of the statement

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score 244 · Answer 15 · 2024-02-01 23:07:12

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Changing the definition of almost sure convergence

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$\forall x(P(x) \rightarrow Q(x))\stackrel{?}{\equiv}\neg\exists x(P(x) \rightarrow \neg Q(x))\stackrel{?}{\equiv}\neg\exists x(P(x) \wedge\neg Q(x))$

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