Question

Difficult Radical Equation

score 2.2k · Answer 1 · 2026-03-19 23:24:52

2.2k

Views

Difficult Radical Equation

Published on 19 Mar 2026 - 23:24

score 488 · Answer 2 · 2026-03-19 23:24:03

488

Views

Solving Radical Inequalities

Published on 19 Mar 2026 - 23:24

score 3.2k · Answer 3 · 2026-03-19 23:26:42

3.2k

Views

Sum of cube roots of complex conjugates

Published on 19 Mar 2026 - 23:26

score 85 · Answer 4 · 2026-03-19 23:27:59

85

Views

How could I find the value of $x$ without squaring both sides given the equation $\sqrt{8} + \sqrt{18} = \sqrt{x}$?

Published on 19 Mar 2026 - 23:27

score 102 · Answer 5 · 2026-03-19 23:27:19

102

Views

Do there exist shorter ways of solving for $x$ (or other smarter methods)?

Published on 19 Mar 2026 - 23:27

score 127 · Answer 6 · 2026-03-19 23:30:26

127

Views

Why can't we remove the radicals from $ \sqrt a + \sqrt b = 8 $ by writing $(\sqrt a)^2 + (\sqrt b)^2 = 8^2$?

Published on 19 Mar 2026 - 23:30

score 239 · Answer 7 · 2026-03-19 23:28:27

239

Views

Finding value of $\lim\limits_{n\rightarrow \infty}\Big(\frac{(kn)!}{n^{kn}}\Big)^{\frac{1}{n}}$

Published on 19 Mar 2026 - 23:28

score 261 · Answer 8 · 2026-02-25 02:29:37

261

Views

Solve $\sqrt{\frac{4-x}x}+\sqrt{\frac{x-4}{x+1}}=2-\sqrt{x^2-12}$

Published on 25 Feb 2026 - 2:29

score 78 · Answer 9 · 2026-03-24 04:41:47

78

Views

Irrational equation

Published on 24 Mar 2026 - 4:41

score 43 · Answer 10 · 2026-03-19 23:24:03

43

Views

Equations involving squaring a variable under a radical sign

Published on 19 Mar 2026 - 23:24

score 106 · Answer 11 · 2026-03-20 04:28:43

106

Views

If $a+\sqrt{a^2+1}= b+\sqrt{b^2+1}$, then $a=b$ or not?

Published on 20 Mar 2026 - 4:28

score 55 · Answer 12 · 2019-02-15 02:03:33

55

Views

How to solve a limit through rationalizing but the radicand is a linear relation and the denominator is a quadratic?

Published on 15 Feb 2019 - 2:03

score 82 · Answer 13 · 2019-02-26 09:05:45

82

Views

Rationalize irrational equation

Published on 26 Feb 2019 - 9:05

score 342 · Answer 14 · 2019-02-28 16:12:43

342

Views

Solve for $x$ : $\sqrt{x-6} \, + \, \sqrt{x-1} \, + \, \sqrt{x+6} = 9$?

Published on 28 Feb 2019 - 16:12

score 99 · Answer 15 · 2019-03-22 05:21:28

99

Views

If $f(x) \in\Bbb Q[x]$ has splitting field of degree $16$ over $\Bbb Q$ is $f(x)$ solvable by radicals?

Published on 22 Mar 2019 - 5:21

List Question

Difficult Radical Equation

Solving Radical Inequalities

Sum of cube roots of complex conjugates

How could I find the value of $x$ without squaring both sides given the equation $\sqrt{8} + \sqrt{18} = \sqrt{x}$?

Do there exist shorter ways of solving for $x$ (or other smarter methods)?

Why can't we remove the radicals from $ \sqrt a + \sqrt b = 8 $ by writing $(\sqrt a)^2 + (\sqrt b)^2 = 8^2$?

Finding value of $\lim\limits_{n\rightarrow \infty}\Big(\frac{(kn)!}{n^{kn}}\Big)^{\frac{1}{n}}$

Solve $\sqrt{\frac{4-x}x}+\sqrt{\frac{x-4}{x+1}}=2-\sqrt{x^2-12}$

Irrational equation

Equations involving squaring a variable under a radical sign

If $a+\sqrt{a^2+1}= b+\sqrt{b^2+1}$, then $a=b$ or not?

How to solve a limit through rationalizing but the radicand is a linear relation and the denominator is a quadratic?

Rationalize irrational equation

Solve for $x$ : $\sqrt{x-6} \, + \, \sqrt{x-1} \, + \, \sqrt{x+6} = 9$?

If $f(x) \in\Bbb Q[x]$ has splitting field of degree $16$ over $\Bbb Q$ is $f(x)$ solvable by radicals?

Trending Questions

Popular # Hahtags

Popular Questions