Question

Simplifying $\left(\frac{a-b}{\sqrt a+\sqrt b}+\sqrt b\right)/\left(\frac{a-b}{\sqrt a+\sqrt b}-\sqrt a\right)$

score 822 · Answer 1 · 2016-11-07 13:36:28

822

Views

Simplifying $\left(\frac{a-b}{\sqrt a+\sqrt b}+\sqrt b\right)/\left(\frac{a-b}{\sqrt a+\sqrt b}-\sqrt a\right)$

Published on 07 Nov 2016 - 13:36

score 273 · Answer 2 · 2016-11-08 04:49:09

273

Views

If $\dfrac x{x^{1.5}}=(8x)^{-1}$ and $x>0$, then $x=\;?$

Published on 08 Nov 2016 - 4:49

score 764 · Answer 3 · 2016-11-08 18:49:16

764

Views

How can you take a square root of a negative number?

Published on 08 Nov 2016 - 18:49

score 29 · Answer 4 · 2016-11-10 09:03:52

29

Views

power and radical functions

Published on 10 Nov 2016 - 9:03

score 1.7k · Answer 5 · 2016-11-13 05:31:08

1.7k

Views

What is the proof that $\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}$ for $a,~ b > 0$?

Published on 13 Nov 2016 - 5:31

score 42 · Answer 6 · 2016-11-13 19:09:50

42

Views

Basic Algebra: square numbers

Published on 13 Nov 2016 - 19:09

score 60 · Answer 7 · 2016-11-15 14:02:17

60

Views

Why (2i)^a/(-2i)^b is not equal to (2i)^a/(2i)^b * 1/(-1)^b?

Published on 15 Nov 2016 - 14:02

score 646 · Answer 8 · 2016-11-16 15:49:41

646

Views

Find limit of $\sqrt[3]{n+1}-\sqrt[3]{n}$

Published on 16 Nov 2016 - 15:49

score 894 · Answer 9 · 2026-03-31 18:21:27

894

Views

Limit of the sequence $a_n=\sqrt[n+1]{(n+1)!}-\sqrt[n]{n!}$

Published on 31 Mar 2026 - 18:21

score 118 · Answer 10 · 2026-03-28 06:22:51

118

Views

Working with square roots

Published on 28 Mar 2026 - 6:22

score 234 · Answer 11 · 2026-03-27 10:44:18

234

Views

$4=5$. Is this possible?

Published on 27 Mar 2026 - 10:44

score 1.9k · Answer 12 · 2026-03-29 21:19:45

1.9k

Views

Limits to infinity of a factorial function: $\lim_{n\to\infty}\frac{n!}{n^{n/2}}$

Published on 29 Mar 2026 - 21:19

score 48 · Answer 13 · 2016-11-19 19:50:56

48

Views

Numbers expressed by a ratio of square roots

Published on 19 Nov 2016 - 19:50

score 70 · Answer 14 · 2016-11-20 04:22:15

70

Views

Why is $ y \le 0$ one of the solutions of the equation $\sqrt{x^2+y^2} = -y $?

Published on 20 Nov 2016 - 4:22

score 263 · Answer 15 · 2016-11-20 09:55:03

263

Views

Does $\lim_{n\rightarrow \infty }\sqrt[n]{a_{n}}=\sqrt[n]{\lim_{n\rightarrow \infty }a_{n}}$ hold?

Published on 20 Nov 2016 - 9:55

List Question

Simplifying $\left(\frac{a-b}{\sqrt a+\sqrt b}+\sqrt b\right)/\left(\frac{a-b}{\sqrt a+\sqrt b}-\sqrt a\right)$

If $\dfrac x{x^{1.5}}=(8x)^{-1}$ and $x>0$, then $x=\;?$

How can you take a square root of a negative number?

power and radical functions

What is the proof that $\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}$ for $a,~ b > 0$?

Basic Algebra: square numbers

Why (2i)^a/(-2i)^b is not equal to (2i)^a/(2i)^b * 1/(-1)^b?

Find limit of $\sqrt[3]{n+1}-\sqrt[3]{n}$

Limit of the sequence $a_n=\sqrt[n+1]{(n+1)!}-\sqrt[n]{n!}$

Working with square roots

$4=5$. Is this possible?

Limits to infinity of a factorial function: $\lim_{n\to\infty}\frac{n!}{n^{n/2}}$

Numbers expressed by a ratio of square roots

Why is $ y \le 0$ one of the solutions of the equation $\sqrt{x^2+y^2} = -y $?

Does $\lim_{n\rightarrow \infty }\sqrt[n]{a_{n}}=\sqrt[n]{\lim_{n\rightarrow \infty }a_{n}}$ hold?

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